The given sequence is an arithmetic sequence with a common difference that increases by 1 with each term. To find the nth term of an arithmetic sequence, you can use the formula: nth term = a + (n-1)d, where a is the first term, n is the term number, and d is the common difference. In this case, the first term (a) is 3 and the common difference (d) is increasing by 1, so the nth term would be 3 + (n-1)(n-1) = n^2 + 2.
The nth term of the sequence is (n + 1)2 + 2.
each time the number increases by 8 and the original number was 3.This means that nth term = 3+(n-1)8ie. the fourth term 27 would be 3 + (4-1)x8 = 3+24 = 27
ans=102 HOW? 6,11,13,27,38,.... 6(+5),11(+7),13(+9),27(+11),38(+13),51(+15),66(+17),83(+19),102adding 5 to 6 gives 11 adding 7(two greater than previous one) gives 13...and so on... to find the nth term N squared +2
Subtract 2 from the sequence and the answer becomes obvious: 1, 4, 9, 16, 25,...,N2 Now, add the 2 back in: 3, 6, 11, 18, 27,...,(N2+2)
n3
The nth term of the sequence is (n + 1)2 + 2.
Subtract 2 from the sequence and the answer becomes obvious: 1, 4, 9, 16, 25,...,N2 Now, add the 2 back in: 3, 6, 11, 18, 27,...,(N2+2)
each time the number increases by 8 and the original number was 3.This means that nth term = 3+(n-1)8ie. the fourth term 27 would be 3 + (4-1)x8 = 3+24 = 27
ans=102 HOW? 6,11,13,27,38,.... 6(+5),11(+7),13(+9),27(+11),38(+13),51(+15),66(+17),83(+19),102adding 5 to 6 gives 11 adding 7(two greater than previous one) gives 13...and so on... to find the nth term N squared +2
(n(n-1) divided by 2 + 1) multiplied by 3) +6
To find the nth term of this sequence, we first need to determine the pattern or rule governing the sequence. By examining the differences between consecutive terms, we can see that the sequence is increasing by 9, 15, 21, 27, and so on. This indicates that the nth term is given by the formula n^2 + 1.
n3
5n+2
Willies
2n +29
There are many possible answers, but the simplest is t(n) = 27 - 8*n where n = 1, 2, 3, ...
3^n These are powers of 3