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Q: What is the number of diagonals that can be drawn from one vertex in a convex polygon that has n vertices?
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Related questions

Does the number of diagonals a polygon has depend on if it is regular?

No, as long as the polygon is convex.


How many curved edges in convex polygon?

None.A polygon is made up of straight line edges between its vertices. There are the same number of edges as vertices in a polygon.In the case of a polygon, it is convex if all interior angles are less than 180o.


How do you find diagonals in a polygon?

Suppose a polygon has n vertices (and sides). From each vertex, a diagonal can be drawn to all vertices, excluding itself and the two adjacent vertices. So n-3 diagonals can be drawn from each vertex. Multiplying by the full complement of n vertices gives n(n-3). However, as things stand we have counted each diagonal twice: once at both ends. Dividing by two gives the actual number of diagonals. number of diagonals = n(n-3)/2


How many diagonals can be drawn from one vertex of a 12 sided polygon?

10 ... any polygon it is 2 less than the number of sides or vertices wince they are the same.


Which polygon has number of sides is equal to the number of diagonals?

The five sided Polygon has 5 diagonals


How many diagonals from one vertex in 16gon?

Using the formula 0.5(n^2 -3n) whereas n is number of sides, altogether there are 104 diagonals in a 16 sided polygon


How many diagonals can be drawn from one vertex of a polygon of 50 sides?

47 sides. Take a vertex of an n-sided polygon. There are n-1 other vertices. It is already joined to its 2 neighbours, leaving n-3 other vertices not connected to it. Thus n-3 diagonals can be drawn in from each vertex. For n=50, n-3 = 50-3 = 47 diagonals can be drawn from each vertex. The total number of diagonals in an n-sided polygon would imply n-3 diagonals from each of the n vertices giving n(n-3). However, the diagonal from vertex A to C would be counted twice, once for vertex A and again for vertex C, thus there are half this number of diagonals, namely: number of diagonals in an n-sided polygon = n(n-3)/2.


What is the formula for the number of diagonals in a polygon?

Suppose a polygon has n vertices (and sides).From each vertex, a diagonal can be drawn to all vertices, excluding itself and the two adjacent vertices. So n-3 diagonals can be drawn from each vertex.Multiplying by the full complement of n vertices gives n(n-3). However, as things stand we have counted each diagonal twice: once at both ends. Dividing by two gives the actual number of diagonals.number of diagonals = n(n-3)/2


How many sides are there in the polygon if the number of diagonals is twice as the number of sides?

A 7 sided polygon has 14 diagonals


How many diagonal can be drawn from a regular hexagon from one vertex?

5 diagonals * * * * * That is not correct since two of these would be lines joining the vertex to adjacent vertices (one on either side). These are sides of the polygon, not diagonals. The number of diagonals from any vertex of a polygon with n sides is n-3.


Is a pentagon convex?

A regular pentagon is convex. By taking a regular pentagon and shortening or lengthening one or more sides, an infinite number of possible convex pentagons can be created. A convex polygon is defined as a polygon such that all internal angles are less than or equal to 180 degrees, and a line segment drawn between any two vertices remains inside the polygon. It is possible to have non-convex (concave) pentagons; there are infinite number possible ways to do this, too.


What is the formula to determine the number of diagonals in a polygon?

It is: 0.5*(n2-3n) = diagonals whereas n is the number of sides of the polygon