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If a polygon has a total of 560 diagonals how many vertices does it have?
The formula to calculate the number of diagonals in a polygon is n(n-3)/2, where n represents the number of vertices. Setting this formula equal to 560 and solving for n, we get n(n-3)/2 = 560. By solving this quadratic equation, we find that the polygon has 20 vertices.
How do you find diagonals in a polygon?
Suppose a polygon has n vertices (and sides). From each vertex, a diagonal can be drawn to all vertices, excluding itself and the two adjacent vertices. So n-3 diagonals can be drawn from each vertex. Multiplying by the full complement of n vertices gives n(n-3). However, as things stand we have counted each diagonal twice: once at both ends. Dividing by two gives the actual number of diagonals. number of diagonals = n(n-3)/2
What is the formula for the number of diagonals in a polygon?
Suppose a polygon has n vertices (and sides).From each vertex, a diagonal can be drawn to all vertices, excluding itself and the two adjacent vertices. So n-3 diagonals can be drawn from each vertex.Multiplying by the full complement of n vertices gives n(n-3). However, as things stand we have counted each diagonal twice: once at both ends. Dividing by two gives the actual number of diagonals.number of diagonals = n(n-3)/2
What is the relationship between the number of sides of a polygon and the number of diagonals?
Number of diagonals = 1/2*(n2-3n) where n = the number of sides of the polygon.
How many diagonals does a 11 sided polygon have?
You can find the number of diagonals in a polygon using the formula n(n-3)/2, where n is the number of sides. Therefore an 11 sided polygon has 44 diagonals.
Does the number of diagonals a polygon has depend on if it is regular?
No, as long as the polygon is convex.
How many curved edges in convex polygon?
None.A polygon is made up of straight line edges between its vertices. There are the same number of edges as vertices in a polygon.In the case of a polygon, it is convex if all interior angles are less than 180o.
If a polygon has a total of 560 diagonals how many vertices does it have?
The formula to calculate the number of diagonals in a polygon is n(n-3)/2, where n represents the number of vertices. Setting this formula equal to 560 and solving for n, we get n(n-3)/2 = 560. By solving this quadratic equation, we find that the polygon has 20 vertices.
How do you find diagonals in a polygon?
Suppose a polygon has n vertices (and sides). From each vertex, a diagonal can be drawn to all vertices, excluding itself and the two adjacent vertices. So n-3 diagonals can be drawn from each vertex. Multiplying by the full complement of n vertices gives n(n-3). However, as things stand we have counted each diagonal twice: once at both ends. Dividing by two gives the actual number of diagonals. number of diagonals = n(n-3)/2
Which polygon has number of sides is equal to the number of diagonals?
The five sided Polygon has 5 diagonals
How many diagonals can be drawn from one vertex of a 12 sided polygon?
10 ... any polygon it is 2 less than the number of sides or vertices wince they are the same.
How many diagonals from one vertex in 16gon?
Using the formula 0.5(n^2 -3n) whereas n is number of sides, altogether there are 104 diagonals in a 16 sided polygon
How many diagonals can be drawn from one vertex of a polygon of 50 sides?
47 sides. Take a vertex of an n-sided polygon. There are n-1 other vertices. It is already joined to its 2 neighbours, leaving n-3 other vertices not connected to it. Thus n-3 diagonals can be drawn in from each vertex. For n=50, n-3 = 50-3 = 47 diagonals can be drawn from each vertex. The total number of diagonals in an n-sided polygon would imply n-3 diagonals from each of the n vertices giving n(n-3). However, the diagonal from vertex A to C would be counted twice, once for vertex A and again for vertex C, thus there are half this number of diagonals, namely: number of diagonals in an n-sided polygon = n(n-3)/2.
What is the formula for the number of diagonals in a polygon?
Suppose a polygon has n vertices (and sides).From each vertex, a diagonal can be drawn to all vertices, excluding itself and the two adjacent vertices. So n-3 diagonals can be drawn from each vertex.Multiplying by the full complement of n vertices gives n(n-3). However, as things stand we have counted each diagonal twice: once at both ends. Dividing by two gives the actual number of diagonals.number of diagonals = n(n-3)/2
How many sides are there in the polygon if the number of diagonals is twice as the number of sides?
A 7 sided polygon has 14 diagonals
How many diagonal can be drawn from a regular hexagon from one vertex?
5 diagonals * * * * * That is not correct since two of these would be lines joining the vertex to adjacent vertices (one on either side). These are sides of the polygon, not diagonals. The number of diagonals from any vertex of a polygon with n sides is n-3.
What is the formula to determine the number of diagonals in a polygon?
It is: 0.5*(n2-3n) = diagonals whereas n is the number of sides of the polygon
