Suppose a polygon has n vertices (and sides).
From each vertex, a diagonal can be drawn to all vertices, excluding itself and the two adjacent vertices. So n-3 diagonals can be drawn from each vertex.
Multiplying by the full complement of n vertices gives n(n-3). However, as things stand we have counted each diagonal twice: once at both ends. Dividing by two gives the actual number of diagonals.
number of diagonals = n(n-3)/2
It is: 0.5*(n2-3n) = diagonals whereas 'n' is the number of sides of the polygon
You can find the number of diagonals in a polygon using the formula n(n-3)/2, where n is the number of sides. Therefore an 11 sided polygon has 44 diagonals.
Use the formula of: 0.5*(n2-3n) whereby n is the number of sides of the polygon
1/2*(n2-3n) where n is the number of sides of the polygon.
The formula used to find the number of diagonals in a polygon is n(n-3)/2. 30 x 27/2 = 810/2 = 405 diagonals.
The formula is: 0.5*(n2-3n) = diagonals whereas n is the number of sides of the polygon
It is: 0.5*(n2-3n) = diagonals whereas n is the number of sides of the polygon
It is: 0.5*(n2-3n) = diagonals whereas 'n' is the number of sides of the polygon
You can find the number of diagonals in a polygon using the formula n(n-3)/2, where n is the number of sides. Therefore an 11 sided polygon has 44 diagonals.
The formula is: 0.5*(n2-3n) where n is the number of sides of the polygon
The formula for the number of diagonals is: 0.5*(n^2-3n) whereas 'n' is the number of sides of the polygon
The formula is: 0.5*(n2-3n) = number of diagonals when n is the number of sides of the polygon
0.5*(n2-3n) where n is equal to the number of sides of the polygon
Use the formula of: 0.5*(n2-3n) whereby n is the number of sides of the polygon
Total diagonals formula: 0.5*(n^2 -3n) whereas n is the number of sides of the polygon
For a 9 sided polygon it is: 0.5*(92-(3*9)) = 27 diagonals
n side polygon has n(n-3)/2 diagonals therefore a hexagon has 9 diagonals