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What is the length and width of a rectangle if the perimeter is 32 feet and the area is 48 square feet?
Length is 12ft, width is 4 ft. 2 x (length + width) = perimeter = 32 ft ⇒ length = 16ft - width [1] length x width = area = 48 sq ft Using [1] above: ⇒ (16ft - width) x width = 48 sq ft multiplying out and rearranging: ⇒ width2 - 16 x width + 48 = 0 factorizing: ⇒ (width - 4)x(width - 12) = 0 Thus width = 4 or 12, so using [1] above: ⇒ width = 4ft, length = 16 - 4 = 12ft or width = 12ft, length = 16 - 12 = 4ft Convention is that the length is larger than the width, thus rectangle is 12ft long by 4 ft wide.
What is the area of a rectangle with a width of 12ft and length of 10ft?
To find the area of a rectangle, multiply length x width: 12 x 10 = 120 sq ft
What is the perimeter of a 12ft long and 15ft wide room?
2*(length + width) = 54 feet.
What is the area of a rectangle with a width of 12 feet and length of 10 feet?
Area=length x width, A=lxw=10ft x 12ft=120ft2
What is the area of a rectangle with a width 12ft and a length of 10ft?
12 x 10 = 120 square feet
How many square feet are in 12ft x 7ft?
To find the area of a rectangle, multiply the length and width. 12ft * 7ft = 84 square feet
What is the area of a rectangle with a width of 12 ft and a length of 10 ft?
A(rect) = w * l = 12ft*10ft = 120ft2Length * width = area10 * 12 = 120
What is the area of a rectangle if the length is 16 ft and the width is 12 ft?
To find the area of your rectangle, multiply 16ft by 12ft. This gives you 192. So your answer would be 192 square feet.
What is the perimeter of a 21ft wide and 12ft long rectangle?
2(21+12) = 66 feet
The length of a rectangle is 12ft longer than twice the width if the perimeter is 108 ft What is the length and the width?
Well, well, well, look who's trying to do some math! Let's cut to the chase - the width of the rectangle is 18ft and the length is 48ft. How did I figure that out? By using my fabulous brain and some good old algebra, honey.
If the area of a rectangle is 264 square feet and the length is 10 feet more then the width what are the dimensions?
Let x be the width of the rectangle. The length will therefore be x + 10 and the volume will be x(x + 10) = x2 + 10x The questuion gives the numeric value for the area as 264, so x2 + 10x = 264 => x2 + 10x - 264 = 0 => (x + 22)(x - 12) = 0 => x = -22 or x = 12. Since only a positive number can be used as a real length, the width of the rectangle is 12ft and the length is 12 + 10 = 22ft. So the dimensions of the rectangle are 22ft x 12ft.
What is the area of a rectangle with the width of 12ft and a length of 10ft?
two sides 12 ft and two sides 10 ft is 120 sq ft (12*10)
