Q: What is the perimeter of a regular octagon with a side length of a?

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64 cm

Multiply the length of one side (7 cm) by the number of side (8) to see that the perimeter is 56 cm. This works because a regular octagon has 8 sides of equal length..

By using the definition of "perimeter": you need to add the lengths of all eight sides. If it is a REGULAR octagon, you multiply the length of any side by 8, since all sides have the same length.

The perimeter would be 64 - since 8 x 8 = 64 !

Length + width = 18 cm so length = 12 cm and width = 6 cm. Presumably the length is the common side so the perimeter of the octagon is 8 x 12 = 96 cm. If the width is the common side then the perimeter of the octagon is 8 x 6 = 48 cm

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If it's a regular octagon, the perimeter is 8 times the length of one side.

The perimeter is 72.

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64 cm

208/8 = 26mm

Assuming that the perimeter of the regular octagon is 32 inches, and since it has 8 sides, then the length of one side of the figure is 32/8 or 4 inches.

Multiply the length of one side (7 cm) by the number of side (8) to see that the perimeter is 56 cm. This works because a regular octagon has 8 sides of equal length..

we know that regular pentagon has 5 equilateral triangle . now ,perimeter of pentagon = 5 Xside . now,perimeter of a regular pentagon with a side length of 7.2 cm . perimeter = 7.2 X 5 =36 cm .