The perimeter is 72.
If it's a regular octagon, the perimeter is 8 times the length of one side.
112 inches, that is if all the sides are the same length .I think.
we make the assumption that all sides are equal length, that is to say it is a regular octagon. Then one side has length 12 if 2 sides have length 23. So the perimeter is 8x12=96 cm
It depends how big it is. But the rule is: Side length x 8 = Perimeter. For example, if one side was eleven centimeters long then the perimeter would be P= 11 x 8. It would be eighty-eight centimeters. Note: This rule only works for regular octagons. If you need to find the perimeter of an irregular octagon, then you have to measure each side and add up the measurements of each side.
Perimeter = 5*25 = 125 km
' 8a ' is.
If a regular octagon has a perimeter of 40cm, then each side is 5 cm.
If it's a regular octagon, the perimeter is 8 times the length of one side.
8*length of side.
80ft
If the permiter of a regular octagon is 8z-16, then the length of each side would be the perimeter / 8 or 2z-2
12ft
64 cm
208/8 = 26mm
Assuming that the perimeter of the regular octagon is 32 inches, and since it has 8 sides, then the length of one side of the figure is 32/8 or 4 inches.
Multiply the length of one side (7 cm) by the number of side (8) to see that the perimeter is 56 cm. This works because a regular octagon has 8 sides of equal length..
we know that regular pentagon has 5 equilateral triangle . now ,perimeter of pentagon = 5 Xside . now,perimeter of a regular pentagon with a side length of 7.2 cm . perimeter = 7.2 X 5 =36 cm .