441 = 3 * 3 * 7 * 7
3x3x7x7
32 x 72 = 441
32*72 = 441
441 = 3 x 3 x 7 x 7
441 = 32 x 72
√441 = √(3^2 × 7^2) = 3 × 7.
The prime factors of 441 are: 3, 7
To find the prime factorization of 441, you start by dividing it by the smallest prime number, which is 3. Dividing, you find that 441 ÷ 3 = 147. Continuing with 147, you again divide by 3 to get 49. Finally, 49 can be factored into 7 × 7. Therefore, the prime factorization of 441 is (3^2 \times 7^2).
The prime factorization of 441 is: 3 x 3 x 7 x 7 or 3^2 x 7^2441=3*3*7*7
The prime factors are: 3 x 3 x 7 x 7
As a product of its prime factors: 3*3*7*7 = 441 Its square root is 21 or as 3*7 as the product of its prime factors
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