3x3x7x7
As a product of its prime factors: 3*3*7*7 = 441 Its square root is 21 or as 3*7 as the product of its prime factors
The Highest Common Factor (HCF) of 441 and 630 is the largest positive integer that divides both numbers without leaving a remainder. To find the HCF, you can use the prime factorization method. The prime factorization of 441 is 3^2 * 7^2, and the prime factorization of 630 is 2 * 3^2 * 5 * 7. To find the HCF, you take the common prime factors with the lowest exponent, which in this case is 3^2 * 7 = 63. Therefore, the HCF of 441 and 630 is 63.
Prime factorization of 90 = 2x3x3x5
Prime factorization for 128 is 27
The prime factorization of 122 is: 2 × 61 The prime factorization of 35 is: 5 × 7 The prime factorization of 120 is: 2 × 2 × 2 × 3 × 5 The prime factorization of 15 is: 3 × 5
441 = 3 * 3 * 7 * 7
32 x 72 = 441
32*72 = 441
441 = 3 x 3 x 7 x 7
√441 = √(3^2 × 7^2) = 3 × 7.
441 = 32 x 72
The prime factors of 441 are: 3, 7
To find the prime factorization of 441, you start by dividing it by the smallest prime number, which is 3. Dividing, you find that 441 ÷ 3 = 147. Continuing with 147, you again divide by 3 to get 49. Finally, 49 can be factored into 7 × 7. Therefore, the prime factorization of 441 is (3^2 \times 7^2).
The prime factorization of 441 is: 3 x 3 x 7 x 7 or 3^2 x 7^2441=3*3*7*7
The prime factors are: 3 x 3 x 7 x 7
As a product of its prime factors: 3*3*7*7 = 441 Its square root is 21 or as 3*7 as the product of its prime factors
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