2 x 2 x 2 = 8
2 x 2 x 5 = 20
The odds of choosing a prime number in the set [1-20] are 8 out of 20, as there are 8 prime numbers, 2, 3, 5, 7, 11, 13, 17, and 19, in that set.
There are 8 out of 20 numbers that are prime, so 8/20, or 2/5.
None. A number that ends with 8 is even, that is, divisible by 2. ================================ To be prime a number must only be divisible by itself and 1 thus any number divisible by 2 can not be a prime number. Therefore the answer to your question is:- "There are no prime numbers between 20 and 200 that end with an 8".
There are eight prime numbers between 1 and 20.2, 3, 5, 7, 11, 13, 17, 19If you randomly choose in number then you have an 8 in 20 chance of selecting a prime.The probability is selecting a prime number is 8/20 or 0.4
The probability is 8/20.
11 13 17 19.
There are 8 prime numbers (2, 3, 5, 7, 11, 13, 17, 19) between 1 and 20, the rest are comp. P(prime then comp) = (8/20) * (11/20) = .22 There is a 22% chance you will draw a prime number followed by a composite number. ...maybe...
8: 1,2,3,5,7,13,17,19
8 is a even number 17 is a prime number
The first prime after 20 is 23.
The first prime number after 8 is 11
In this problem, the total number of possibilities is 20, so n = 20.The set of prime numbers from 1 to 20 = {2, 3, 5, 7, 11, 13, 17, 19}, so f = 8Probability = f/n = 8/20 = 0.4.You have a 2 in 5 chance of choosing a prime number from 1 to 20.