There are eight prime numbers between 1 and 20.
2, 3, 5, 7, 11, 13, 17, 19
If you randomly choose in number then you have an 8 in 20 chance of selecting a prime.
The probability is selecting a Prime number is 8/20 or 0.4
The probability is 8/20.
There are 8 out of 20 numbers that are prime, so 8/20, or 2/5.
The probability of selecting a red card is 26 in 52 or 1 in 2. The probability of selecting an even card is 20 in 52 or 5 in 13. The probability, therefore, of selecting a red even card is 1 in 2 times 5 in 13 or 5 in 26.
The theoretical probability of randomly picking each color marble is the number of color marbles you have for each color, divided by the total number of marbles. For example, the probability of selecting a red marble is 3/20.
1 out of 20 this is because there are 20 numbers in total, and there is only one 7 in there. (Assuming that there is the same probability for each number to be chosen, and that 17 is excluded as an affirmative outcome)
The probability is 8/20.
40%
There are 20 numbers from 20 through 39, and 4 of them are prime (23, 29, 31, 37), the probability is 4 in 20 or 0.20.
The probability of selecting a 17 (or any number for that matter) is 1/20 or .05 or 5%.
There are 8 out of 20 numbers that are prime, so 8/20, or 2/5.
There are 12 composite (and 8 primes) in the first twenty whole numbers. So the probability of randomly choosing a non-prime is 12/20 or 60%.
To find the probability of selecting a number from 20 to 30 that is divisible by 3, we first identify the numbers in that range: 21, 24, 27, and 30. There are four suitable candidates, so the probability of selecting one of them is 4 out of 11 (the total numbers from 20 to 30, inclusive). After replacing the selected number, we check which of these are divisible by 12. Among the numbers listed, only 24 is divisible by 12. Therefore, the probability of selecting a number divisible by 3 and then finding it divisible by 12 is 1 out of 11, which simplifies to approximately 0.0909 or 9.09%.
30% chance. First, find the factors of 20: {1,2,4,5,10,20} There are 6 factors, out of 20 possible numbers. 6/20 = .3 = 30%
The probability of selecting a red card is 26 in 52 or 1 in 2. The probability of selecting an even card is 20 in 52 or 5 in 13. The probability, therefore, of selecting a red even card is 1 in 2 times 5 in 13 or 5 in 26.
In the sample space [1,20], there are 8 prime numbers, [2,3,5,7,11,13,17,19]. The probability, then, of randomly choosing a prime number in the sample space [1,20] is (8 in 20), or (2 in 5), or 0.4. The probability of choosing two of them is (8 in 20) times (7 in 19) which is (56 in 1064) or (7 in 133) or about 0.05263.
In this problem, the total number of possibilities is 20, so n = 20.The set of prime numbers from 1 to 20 = {2, 3, 5, 7, 11, 13, 17, 19}, so f = 8Probability = f/n = 8/20 = 0.4.You have a 2 in 5 chance of choosing a prime number from 1 to 20.
There are 20 numbers in total from 1 to 20. The even numbers in this range are 2, 4, 6, 8, 10, 12, 14, 16, 18, and 20, totaling 10 even numbers. Therefore, the probability of picking an even number is the number of even numbers divided by the total numbers, which is ( \frac{10}{20} = \frac{1}{2} ). Thus, the probability of selecting an even number is 0.5 or 50%.