To find the probability of selecting a multiple of 2 or 3 from the numbers 1 to 10, first identify the multiples: the multiples of 2 are 2, 4, 6, 8, and 10; the multiples of 3 are 3, 6, and 9. The number 6 is counted in both categories, so the unique multiples of 2 or 3 are 2, 3, 4, 6, 8, 9, and 10, totaling 7 unique numbers. Since there are 10 possible selections, the probability is 7/10 or 0.7.
In the range of 1 to 10, there are five odd numbers: 1, 3, 5, 7, and 9. Since there are a total of 10 numbers, the probability of selecting an odd number is the number of odd outcomes divided by the total outcomes. This gives us a probability of 5/10, which simplifies to 1/2 or 50%.
Let P(A) = 1/10; P(A) = probability of selecting one people on a basketball team P(B) = 1/35; P(B) = probability of selecting one people on a football team P(C) = 1/10 = probability of selecting one people who plays in both teams P(D) = probability of selecting from either team. P(D) = P(A) + P(B) - P(C) P(D) = 1/10 + 1/35 - 1/10 P(D) = 1/35 or 0.0286
In a spinner numbered from 1 to 10, the multiples of 5 are 5 and 10. There are 2 favorable outcomes (5 and 10) out of a total of 10 possible outcomes. Therefore, the probability of landing on a multiple of 5 is 2 out of 10, which simplifies to 1/5 or 0.2. Thus, the probability is 20%.
The probability of an event, such as selecting a multiple of two from a set of numbers, depends on the size of the set and how many of those numbers are multiples of two. For example, in the set of integers from 1 to 10, there are five multiples of two (2, 4, 6, 8, 10). Thus, the probability P(multiple of two) in this case would be 5 out of 10, or 0.5. To determine the probability in a different context, simply apply the same principle by counting the multiples of two in the given set and dividing by the total number of elements in that set.
To find the probability of randomly selecting the letters S, N, O, and T in that specific order from the letters in "FOUNDATIONS," we first note that there are 12 letters in total. The probability of selecting S first is 1/12, then N (1/11), O (1/10), and T (1/9). Therefore, the probability of selecting S, N, O, and T in that order is (1/12) * (1/11) * (1/10) * (1/9) = 1/11880, or approximately 0.000084.
To find the probability of not selecting a multiple of 2 or a multiple of 3 from the numbers 1 to 10, we first identify the multiples: the multiples of 2 are 2, 4, 6, 8, 10, and the multiples of 3 are 3, 6, 9. The multiples of either 2 or 3 are 2, 3, 4, 6, 8, 9, and 10, totaling 7 numbers. This leaves us with 1, 5, and 7 as the numbers that are neither, giving us 3 favorable outcomes. Therefore, the probability is 3 out of 10, or 0.3.
In the range of 1 to 10, there are five odd numbers: 1, 3, 5, 7, and 9. Since there are a total of 10 numbers, the probability of selecting an odd number is the number of odd outcomes divided by the total outcomes. This gives us a probability of 5/10, which simplifies to 1/2 or 50%.
Let P(A) = 1/10; P(A) = probability of selecting one people on a basketball team P(B) = 1/35; P(B) = probability of selecting one people on a football team P(C) = 1/10 = probability of selecting one people who plays in both teams P(D) = probability of selecting from either team. P(D) = P(A) + P(B) - P(C) P(D) = 1/10 + 1/35 - 1/10 P(D) = 1/35 or 0.0286
In a spinner numbered from 1 to 10, the multiples of 5 are 5 and 10. There are 2 favorable outcomes (5 and 10) out of a total of 10 possible outcomes. Therefore, the probability of landing on a multiple of 5 is 2 out of 10, which simplifies to 1/5 or 0.2. Thus, the probability is 20%.
The probability of an event, such as selecting a multiple of two from a set of numbers, depends on the size of the set and how many of those numbers are multiples of two. For example, in the set of integers from 1 to 10, there are five multiples of two (2, 4, 6, 8, 10). Thus, the probability P(multiple of two) in this case would be 5 out of 10, or 0.5. To determine the probability in a different context, simply apply the same principle by counting the multiples of two in the given set and dividing by the total number of elements in that set.
The probability of selecting a red card is 26 in 52 or 1 in 2. The probability of selecting an even card is 20 in 52 or 5 in 13. The probability, therefore, of selecting a red even card is 1 in 2 times 5 in 13 or 5 in 26.
To find the probability of randomly selecting the letters S, N, O, and T in that specific order from the letters in "FOUNDATIONS," we first note that there are 12 letters in total. The probability of selecting S first is 1/12, then N (1/11), O (1/10), and T (1/9). Therefore, the probability of selecting S, N, O, and T in that order is (1/12) * (1/11) * (1/10) * (1/9) = 1/11880, or approximately 0.000084.
There are 10 letters in the word "aspiration" and 5 of them are vowels. The probability of a randomly-selected letter being a vowel are 5/10 = 1/2 = 0.50.
The statement about the probability of selecting the letter 'z' from the alphabet being 126 is incorrect. The probability of selecting any one specific letter from the 26 letters of the English alphabet is 1/26, not 126. Therefore, the probability of selecting 'z' is approximately 0.0385, or about 3.85%.
From a 52 card deck, probability is 1/52.
To calculate the probability of spinning a multiple of 3 on a spinner labeled 1 through 10, we first determine the total number of favorable outcomes. The multiples of 3 between 1 and 10 are 3, 6, and 9. Therefore, there are 3 favorable outcomes. Since there are a total of 10 equally likely outcomes on the spinner, the probability of spinning a multiple of 3 is 3/10 or 0.3.
P (selecting a king) = 4/52 = 1/13