0
What is the probability that a far six-sided die rolled until the first 5 occurs on the tenth roll?
Wiki User
∙ 10y ago
Assuming that the die is fair rather than far, the probability is (5/6)9(1/6) = 1,953,125/60,466,176 = 0.0323 approx.
Wiki User
∙ 10y ago
Add your answer:
Earn +20 pts
You rolled doubles with a pair of dice what is the probability that the total is less than 9?
You have rolled doubles so the full set of possible outcomes is [1,1], [2,2], [3,3], [4,4],[5,5] and [6,6] - that is six in all. Of these the first four are favourable outcomes (sum < 9) So the required probability is 4/6 or 2/3
If You roll a fair number cube twice What is the probability of rolling two threes if the first roll is a 5?
2/36 what you rolled the first time has nothing to do with the next roll. It's an independent event.
Odds of rolling doubles with three dice?
There are 36 possible combinations of unique dice rolls (where order doesn't matter, so sorted/deduped). 6 of these are potentially doubles. The total odds are 1/6 (~16.7%). This is because the probability that any of the two die matched any of the other two dice is really just the probability that a die is the same as another die, which is 1/6. Think about it this way, if you rolled two dice the probability that the first one is the same as the second one is 1/6. If you rolled a one, and then rolled a second die and it didn't come up as the first one, but then you rolled a third one you'll find that the probability that doubles occurred is the probability that the first one matches the third one, OR the second one matches the third one IIF the second one did not match the first one, but because they're independent events it's still just what's the probability that doubles occurred between the comparison rather than the set. This does not take into account triplets being considered doubles. If the potential for triplets is considered (the probability that any two die will have the same value), this becomes a very simple problem because it deals with the likelihood that something can't occur in any form rather than the likelihood that a specific subset will occur. It's simply the probability (after sorting) that the first one is like the second one, or the second one is like the third one. When you think about that, that's really just the probability that all numbers will be different. This means we only have to care about two. The probability that the second is different is 5/6, while the probability that the third is different than both of the first two is 4/6. That makes the probability that no two are alike 5/6 by 4/6. This means that the probability that AT LEAST two are alike is 1 - (5/6 * 4/6), which is 44.444..%. It's an extremely simplified version of the birthday problem.
If two dice were rolled what is the probability of a sum of 10 being rolled?
In order to get a ten, your first die must be either a 4, 5, or 6. The odds on that happening are 3/6, or 1/2. Your second die must then equal six minus the first die. Your odds on that are 1/6. Your overall odds then are 1/2 * 1/6, or 1/12.
If two eight-sided dice are to be rolled On any roll what is the probability of getting two different numbers?
The first dice can show any of the eight numbers. If the dice are to show different numbers the second dice has 7 different numbers out of a possible 8 to chose from. So the probability is 7/8 or 0.875 or 87.5% chance.
What is the probability that a far six sided die rolled until the first 5 occurs on the tenth roll?
For the first 5 to appear on the tenth roll, the first nine rolls must not be a 5 and the tenth must. Therefore: probability = (5/6)9 x 1/6 ≈ 0.0323 = 3.23 %
What is the probability of rolling the same number when three number cubes are rolled?
The first roll doesn't matter for probability, it just sets the number to be rolled by the other two. So: P(rolling the same number three times) = P(rolling a particular number)2 = (1/6)2 = 1/36
You rolled doubles with a pair of dice what is the probability that the total is less than 9?
You have rolled doubles so the full set of possible outcomes is [1,1], [2,2], [3,3], [4,4],[5,5] and [6,6] - that is six in all. Of these the first four are favourable outcomes (sum < 9) So the required probability is 4/6 or 2/3
If a game there are two fair number cubes that are rolled To make the first move you need to roll a total of 6 or 7 or 8 What is the probability that you will be able to make the first move?
Three out of twelve
If You roll a fair number cube twice What is the probability of rolling two threes if the first roll is a 5?
2/36 what you rolled the first time has nothing to do with the next roll. It's an independent event.
Two number cubes are rolled what is probubility of 1 and 2?
First of all it is probability second of all the answer is 1/6+1/6 which is 2/12 which simplified is 1/6
Describe the difference between the probability that an event occurs and the odds in favor of an even?
odds in favor is when the number you want is first and the number out of is last.
Odds of rolling doubles with three dice?
There are 36 possible combinations of unique dice rolls (where order doesn't matter, so sorted/deduped). 6 of these are potentially doubles. The total odds are 1/6 (~16.7%). This is because the probability that any of the two die matched any of the other two dice is really just the probability that a die is the same as another die, which is 1/6. Think about it this way, if you rolled two dice the probability that the first one is the same as the second one is 1/6. If you rolled a one, and then rolled a second die and it didn't come up as the first one, but then you rolled a third one you'll find that the probability that doubles occurred is the probability that the first one matches the third one, OR the second one matches the third one IIF the second one did not match the first one, but because they're independent events it's still just what's the probability that doubles occurred between the comparison rather than the set. This does not take into account triplets being considered doubles. If the potential for triplets is considered (the probability that any two die will have the same value), this becomes a very simple problem because it deals with the likelihood that something can't occur in any form rather than the likelihood that a specific subset will occur. It's simply the probability (after sorting) that the first one is like the second one, or the second one is like the third one. When you think about that, that's really just the probability that all numbers will be different. This means we only have to care about two. The probability that the second is different is 5/6, while the probability that the third is different than both of the first two is 4/6. That makes the probability that no two are alike 5/6 by 4/6. This means that the probability that AT LEAST two are alike is 1 - (5/6 * 4/6), which is 44.444..%. It's an extremely simplified version of the birthday problem.
Two dice are rolled what is the probability of rolling at least one six?
First calculate the probability of not rolling a six - since there are 5 possibilities for each die, this is (5/6) x (5/6). Then calculate the complement (1 minus the probability calculated).First calculate the probability of not rolling a six - since there are 5 possibilities for each die, this is (5/6) x (5/6). Then calculate the complement (1 minus the probability calculated).First calculate the probability of not rolling a six - since there are 5 possibilities for each die, this is (5/6) x (5/6). Then calculate the complement (1 minus the probability calculated).First calculate the probability of not rolling a six - since there are 5 possibilities for each die, this is (5/6) x (5/6). Then calculate the complement (1 minus the probability calculated).
You roll two number cubes what is the probability that you roll a 1 first and a 2 second?
Since there are 6 sides on every die that are equally likely to be rolled, the probability of rolling any given side once is exactly 1/6. The 2 events or the first and second dice roll are independent (the outcome of one does not influence the other) so to find the probability of both occurring you just multiply the probability of each event. Since each event has a 1/6 probability of occurring as stated before, The entire event has a probability of 1/6*1/6 or 1/36, which is approximately 2.78%.
A six sided die is rolled twice what is the probability of rolling either an even number on the first roll or a 1 on the second roll the answer is 7 over 12 but I can't figure out how to get there?
The question asks "What is the probability of rolling either an even number on the first roll or a 1 on the second roll?" These events are independent from each other as the outcome of the second roll is not affected by the outcome of the first roll. However, these events are non-mutually exclusive, meaning that these events can both occur at the same time.The probability of rolling an even number on the first roll is 3/6 because 2, 4, and 6 are even numbers and a six-sided die has six possible numbers.The probability of rolling a 1 on the second roll is 1/6.If these two probabilities are added together, we will have "double counted" the event where an even number is rolled on the first roll and a 1 is rolled on the second roll. To correct for this, we must subtract the probability of both events occurring.The probability that both events occur is 3/36, because 3/6 * 1/6 = 3/36.Now, the probability of rolling either an even number on the first roll or a 1 on the second roll is:3/6 + 1/6 - 3/36= 18/36 + 6/36 - 3/36= 21/36= 7/12
If two dice were rolled what is the probability of a sum of 10 being rolled?
In order to get a ten, your first die must be either a 4, 5, or 6. The odds on that happening are 3/6, or 1/2. Your second die must then equal six minus the first die. Your odds on that are 1/6. Your overall odds then are 1/2 * 1/6, or 1/12.
