The product of the roots of the equation 2x2 -x -2 = 2 is 2x2 -x -2 = 2.
There are 2 roots to the equation x2-4x-32 equals 0; factored it is (x-8)(x+4); therefore the roots are 8 & -4.
It is a quadratic equation with one unknown variable, x which has no real roots.
2x2 - 5x - 3 = 0 A quadratic equation expressed in the form ax2 + bx + c = 0 has two real and distinct roots when b2 - 4ac is positive. Using the figures from the supplied equation then b2 - 4ac = 52 - (4 x 2 x -3) = 25 + 24 = 49. Therefore there are TWO real and distinct roots.
If p, q, r, ... are the roots of the equations, then (x-p), (x-q), (x-r), etc are the factors (and conversely).
Use the quadratic formula, with a = 1, b = -3, c = 2.
-4,3 are the roots of this equation, so for the values for which the sum of roots is 1 & product is -12
the sum is -b/a and the product is c/a
If the quadratic is ax2 + bx + c = 0 then the product of the roots is c/a.
There are 2 roots to the equation x2-4x-32 equals 0; factored it is (x-8)(x+4); therefore the roots are 8 & -4.
They are called the solutions or roots of the equations.
It has roots x = 2.618 and x = 0.38197
This quadratic equation has no real roots because its discriminant is less than zero.
A quadratic equation has the form: x^2 - (sum of the roots)x + product of the roots = 0 or, x^2 - (r1 + r2)x + (r1)(r2) = 0
The roots are: x = -5 and x = -9
The roots of the equation are [5 +/- sqrt(11)]/2 = 4.158 and 0.842
2x2 -3x - 4 = 0 use the qudratic equation and your answers are 1.137458609 and -2.637458609
If you mean b^2 -4ac then it is the discriminant of a quadratic equation. If the discriminant equals 0 then the equation has 2 equal roots. If the discriminant is greater than 0 then the equation has 2 different roots. If the discriminant is less than 0 then it has no real roots.