2x2 - 5x - 3 = 0
A quadratic equation expressed in the form ax2 + bx + c = 0 has two real and distinct roots when b2 - 4ac is positive.
Using the figures from the supplied equation then b2 - 4ac = 52 - (4 x 2 x -3) = 25 + 24 = 49.
Therefore there are TWO real and distinct roots.
It has two complex roots.
A cubic has from 1 to 3 real solutions. The fact that every cubic equation with real coefficients has at least 1 real solution comes from the intermediate value theorem. The discriminant of the equation tells you how many roots there are.
There are infinitely many answers and they comprise the coordinates of all points on the line that satisfy the equation.
There must be fewer independent equation than there are variables. An equation in not independent if it is a linear combination of the others.
It has the following solutions.
2 roots
A quadratic equation has two roots. They may be similar or dissimilar. As the highest power of a quadratic equation is 2 , there are 2 roots. Similarly, in the cubic equation, the highest power is 3, so it has three equal or unequal roots. So the highest power of an equation is the answer to the no of roots of that particular equation.
normally an equation with the x value squared there would be two roots. the two roots are positive 1 and postitive 1. since they are they same number there is actually only one root.
Quadratics can two, one or no real roots.
It has no real roots.
Such an equation has a total of six roots; the number of real roots must needs be even. Thus, depending on the specific equation, the number of real roots may be zero, two, four, or six.
It will have two equal roots.
Factors are (x - 1)(x - 1) so only one root.
That is not an equation, since it doesn't have an equal sign.
The equation [ y = x2 - 2x + 5 ] has an infinite number of solutions,corresponding to every point on the graph of it.The ROOTS corresponding to the two values of 'x' that satisfy the equation when y=0 ...in other words, the points where the graph crosses the x-axis.In the particular case of this equation, the graph doesn't cross the x-axis at all,and the roots are not real numbers. There are still two of them, and they arecomplex conjugates.The roots areX = 1 ± 2 i
It has two complex roots.
A quadratic equation can have a maximum of 2 solutions. If the discriminant (b2-4ac) turns out to be less than 0, the equation will have no real roots. If the Discriminant is equal to 0, it will have equal roots. But, if the discriminant turns out to be more than 0,then the equation will have unequal and real roots.