answersLogoWhite

0

The equation must have roots of x = -1 and x = 5

So: x + 1 = 0 and x - 5 = 0

Therefore: (x + 1)(x - 5) = 0

Expanding the brackets gives the equation:

x2 - 4x - 5 = 0

User Avatar

Wiki User

14y ago

Still curious? Ask our experts.

Chat with our AI personalities

FranFran
I've made my fair share of mistakes, and if I can help you avoid a few, I'd sure like to try.
Chat with Fran
EzraEzra
Faith is not about having all the answers, but learning to ask the right questions.
Chat with Ezra
RafaRafa
There's no fun in playing it safe. Why not try something a little unhinged?
Chat with Rafa

Add your answer:

Earn +20 pts
Q: What is the quadratic equation with the solutions -1 an 5?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Continue Learning about Geometry

What is the area of the square whose side measures 2x-5 cm?

It is: (2x-5)(2x-5) = 2.5 square cm when solved as a quadratic equation


What is 10x squared -29x plus 10 equals 0 when factored and its solutions?

Equation: 10x^2 -29x +10 = 0 When factored: (2x-5)(5x-2) = 0 Its solutions: x = 5/2 or x = 2/5


What is the equation of the line that goes through 3 1 and is parallel to the line 3x plus 5y equals 6?

Known equation: 3x+5y = 6 or y = -3/5x +6/5 Slope of equation: -3/5 Slope of parallel equation: -3/5 Parallel equation: y-1 = -3/5(x-3) => 5y = -3x+14 Parallel equation in its general form: 3x+5y-14 = 0


How do you find the standard form of a linear equation knowing only the y intercept and the slope IE A line has a slope of 5 over 3 and a y intercept of 1 over 2 State the equation in standard form?

Since we know the slope, m = 5/3, and the y-intercept 1/2, we arw able to write the equation of the line in the slope-intercept form, y = mx + b, so we have y = (5/3)x + 1/2.The standard form of the equation of the line is Ax + By = C.y = (5/3)x + 1/2y - y - 1/2 = (5/3)x - y + 1/2 - 1/2-1/2 = (5/3)x - y or(5/3)x - y = -1/2Thus, the standard form, Ax + By = C, of the equation of the line is (5/3)x - y = -1/2.


How do you graph a quadratic equation?

A quadratic equation is an equation with the form: y=Ax2+Bx+C The most important point when graphing a parabola (the shape formed by a quadratic) is the vertex. The vertex is the maximum or minimum of the parabola. The x value of the vertex is equal to -B/(2A). Once you have the x value, just plug it back into the original equation to get the corresponding y value. The resulting ordered pair is the location of the vertex. A parabola will be concave up (pointed downward) if A is +. It will be concave down (pointed upward) if A is -. It is often helpful to find the zeroes of a function when graphing. This can be done by factoring or using the quadratic formula. For every n units away from the vertex on the x-axis, the corresponding y value goes up (or down) by n2*A. Parabolas are symetrical along the vertex, which means that if one point is n units from the vertex, the point -n units from the vertex has the same y value. As an example take the following quadratic: 2x2-8x+3 A=2, B=-8, and C=3 The x value of the vertex is -B/2A=-(-8)/(2*2)=2 By plugging 2 into the original equation we get that the vertex is at (2,-5) 3 units to the right (x=5) has a y value of -5+32*2=13. This means that 3 units to the left (x=-1) has the same y value (-1,13). If you need a clearer explanation, ask a math teacher.