x = zero and x = 13.
x2 - 13x = 0x (x - 13) = 0x = 0andx = 13
It's a quadratic expression: x²+13x+12 If, for example, x²+13x+12 = 0 then there are 2 roots, x=-1 and x=-12
42 + x2 = 13x ∴ x2 - 13x + 42 = 0 ∴ (x - 6)(x - 7) = 0 ∴ x ∈ {6, 7}
x^2 + 13x + 30 = 0 x^2 + 10x + 3x + 30 = 0 x(x + 10) + 3(x + 10) = 0 (x + 3)(x + 10) = 0 x = -3 or x = -10
6.50 to the nearest hundredth (4.685 & 1.815)
Using the discriminant of b^2 -4ac = 0 the value of k works out as -2
If: 6x^2 +2x +k = 0 has equal roots Then using the discriminant of b^2 -4ab=0: 4 -24k=0 => k=-4/-24 => k=1/6 Therefore the value of k = 1/6
The roots will be equal
No, unless "a" happens to be equal to 0, or to 1.
3x squared - 12x - 24 = 0, and -b/a = sum of the roots, and c/a = product of the roots
Using the discriminant the possible values of k are -9 or 9
x2 + 13x = -30 ∴ x2 + 13x + 30 = 0 ∴ (x + 3)(x + 10) = 0 ∴ x ∈ {-3, -10}