It's a quadratic expression: x²+13x+12
If, for example, x²+13x+12 = 0 then there are 2 roots, x=-1 and x=-12
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x2 - 13x = 0x (x - 13) = 0x = 0andx = 13
2x2 + 13x - 7 = zero(2x - 1 )( x + 7 ) = zero2x - 1 = zerox = 1/2x + 7 = zerox = -7
Let square = [x] -4+3*(-2)*[-4]+[3x-2x]=-4-6-2+[x]=-12+[x]The answer is negative 12 plus squared x.
x2 + 13x + 40 = x2 + 5x + 8x + 40 = x(x + 5) + 8(x + 5) = (x + 8)(x + 5)
x2 + 13x + 36 = 0 so (x+4)(x+9) = 0 so that x = -4 or x = -9