If for example the roots where x = 2 or x =5 then within the brackets this would be (x-2)(x-5) = 0 and by multiplying out the brackets the quadratic equation comes to x2-7x+10 = 0
Generally, no. But one of the infinite roots of 1 is 1. Otherwise one of the roots would be nearly 1. Just a whisker smaller than 1 if it was the root of a number between 0 and 1, and just a whisker larger if the number was greater than 1. If the number was less than 0, then the roots would vary from the real to the complex numbers.
If you mean b^2 -4ac then it is the discriminant of a quadratic equation. If the discriminant equals 0 then the equation has 2 equal roots. If the discriminant is greater than 0 then the equation has 2 different roots. If the discriminant is less than 0 then it has no real roots.
The discriminant is the part of the quadratic formula which shows whether you will have two real roots, one real root, or no real roots. X = -b +/- sqrt(b^2-4ac)/2a just use the part under the radical as the discriminant b^2 - 4ac of the answer is; answer > 0-----then two real roots answer = 0-----then one real root answer > 0-----then no real roots
But there will be a solution if the discriminant is equal to zero: Real and different roots if b2-4ac > 0 Real and equal roots if b2-4ac = 0 But no real roots if b2-4ac < 0 in other words the graph wont make contact with or intercept the x axis.
Whether the equation has 2 distinct roots, repeated roots, or complex roots. If the determinant is smaller than 0 then it has complex roots. If the determinant is 0 then it has repeated roots. If the determinant is greater than 0 then it has two distinct roots.
For a quadratic equation the discriminant is: b2-4ac If it's = 0 then the roots are equal If it's < 0 then there are no roots If it's > 0 then there are two different roots
Differenzdruck- Messumformer 0-25 Pa bis 0-100 kPa
The discriminant of the quadratic equation ax2+bx+c = 0 is the value of b2-4ac When b2-4ac = 0 then there are 2 equal roots. When b2-4ac > 0 then there are 2 different roots. When b2-4ac < 0 then there are no roots at all.
If for example the roots where x = 2 or x =5 then within the brackets this would be (x-2)(x-5) = 0 and by multiplying out the brackets the quadratic equation comes to x2-7x+10 = 0
Generally, no. But one of the infinite roots of 1 is 1. Otherwise one of the roots would be nearly 1. Just a whisker smaller than 1 if it was the root of a number between 0 and 1, and just a whisker larger if the number was greater than 1. If the number was less than 0, then the roots would vary from the real to the complex numbers.
It is: 0
There will be 2 real roots
x2 + 11x + 30 = 0 (x + 5)(x + 6) = 0 so the roots are -5 and -6
To find which has imaginary roots, use the discriminant of the quadratic formula (b2 - 4ac) and see if it's less than 0. (The quadratic formula corresponds to general form of a quadratic equation, y = ax2 + bx + c)A) x2 - 1 = 0= 0 - 4(1)(-1) = 4Therefore, the roots are not imaginary.B) x2 - 2 = 0= 0 - 4(1)(-2) = 8Therefore, the roots are not imaginary.C) x2 + x + 1 = 0= 1 - 4(1)(1) = -3Therefore, the roots are imaginary.D) x2 - x - 1 = 0= 1 - 4(1)(-1) = 5Therefore, the roots are not imaginary.The equation x2 + x + 1 = 0 has imaginary roots.
A quadratic equation has the form: x^2 - (sum of the roots)x + product of the roots = 0 or, x^2 - (r1 + r2)x + (r1)(r2) = 0
A volcano with a VEI of 0 would be a gentle out pouring of lava from a cone, meanwhile a 8 is a supervolcano.