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How do you determine quadratic eqauation given the roots?
If for example the roots where x = 2 or x =5 then within the brackets this would be (x-2)(x-5) = 0 and by multiplying out the brackets the quadratic equation comes to x2-7x+10 = 0
Is it possible to get an infinite root of a number?
Generally, no. But one of the infinite roots of 1 is 1. Otherwise one of the roots would be nearly 1. Just a whisker smaller than 1 if it was the root of a number between 0 and 1, and just a whisker larger if the number was greater than 1. If the number was less than 0, then the roots would vary from the real to the complex numbers.
In the quadratic equation ax2 plus bx plus c 0 if b2 - 4ac?
If you mean b^2 -4ac then it is the discriminant of a quadratic equation. If the discriminant equals 0 then the equation has 2 equal roots. If the discriminant is greater than 0 then the equation has 2 different roots. If the discriminant is less than 0 then it has no real roots.
What is the discrimenant?
The discriminant is the part of the quadratic formula which shows whether you will have two real roots, one real root, or no real roots. X = -b +/- sqrt(b^2-4ac)/2a just use the part under the radical as the discriminant b^2 - 4ac of the answer is; answer > 0-----then two real roots answer = 0-----then one real root answer > 0-----then no real roots
Why if the discriminant is zero is there no solution to the quadratic equation?
But there will be a solution if the discriminant is equal to zero: Real and different roots if b2-4ac > 0 Real and equal roots if b2-4ac = 0 But no real roots if b2-4ac < 0 in other words the graph wont make contact with or intercept the x axis.
