The sum of the exterior angles of a polygon is 360°.
There are the same number of exterior angles as there are sides.
For a regular polygon all the angles are the same size:
→ number_of_sides × exterior_angle = 360°
→ exterior_angle = 360° ÷ number_of_sides
→ exterior_angle = 360° ÷ 5 = 72°
Exterior angle = 360/Number of sides = 360/5 = 72 degrees. Interior angle = 180 - Exterior angle = 180 - 72 = 108 degrees.
thirty sixImproved Answer:-Providing that it's a regular pentagon then each interior angle will measure 108 degrees
Exterior angle = 14.4 degrees Interior angle = 165.6 degrees
Providing that it is a regular 6 sided hexagon then each exterior angle measures 60 degrees
162 degrees
Exterior angle = 360/Number of sides = 360/5 = 72 degrees. Interior angle = 180 - Exterior angle = 180 - 72 = 108 degrees.
Interior angles are 108o. 360 - 108 = 252o for each exterior angle * * * * * Each exterior angle is 360/5 = 72 degrees, NOT 252. The 108 for the interior angle is correct, but to get from interior to exterior you subtract from 180, not 360!
108'
thirty sixImproved Answer:-Providing that it's a regular pentagon then each interior angle will measure 108 degrees
Each exterior angle is 360/6 = 60 degrees
135 degrees and its exterior angle is 45 degrees
Exterior angles are supplementary with interior angles, so 180-30=150
Exterior angle = 14.4 degrees Interior angle = 165.6 degrees
exterior angle = 360° ÷ 20 sides = 18° interior angle = 180° - exterior angle = 180° - 18° = 162°
To the nearest tenth, the interior angle of a regular pentagon is 108.0o In a regular pentagon, the sum of the interior angles is (5 - 2) x 1800 = 3 x 1800 = 540o In a regular pentagon, the interior angles are all the same size and are 5400 ÷ 5 = 108o which to the nearest tenth is 108.0o
Providing that it is a regular 6 sided hexagon then each exterior angle measures 60 degrees
The easiest way to calculate this is to calculate the exterior angle and use the fact that the exterior and interior angles are supplementary. Sum exterior angles = 360° → Each exterior angle of a regular 28-agon is 360° ÷ 28 → Each interior angle of a regular 28-agon = 180° - 360° ÷ 28 = 167 1/7° ≈ 167.14°