answersLogoWhite

0


Best Answer

The sum of the exterior angles of a polygon is 360°.

There are the same number of exterior angles as there are sides.

For a regular polygon all the angles are the same size:

→ number_of_sides × exterior_angle = 360°

→ exterior_angle = 360° ÷ number_of_sides

→ exterior_angle = 360° ÷ 5 = 72°

User Avatar

Wiki User

6y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: What is the size of an exterior Angle in a regular pentagon?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

What is the size of each interior angle at each vertex of a regular pentagon?

Exterior angle = 360/Number of sides = 360/5 = 72 degrees. Interior angle = 180 - Exterior angle = 180 - 72 = 108 degrees.


What is the size of each exterior angle of a regular pentagon?

Interior angles are 108o. 360 - 108 = 252o for each exterior angle * * * * * Each exterior angle is 360/5 = 72 degrees, NOT 252. The 108 for the interior angle is correct, but to get from interior to exterior you subtract from 180, not 360!


Size of interior angle of regular pentagon?

108'


What is the size of each interior angle in a pentagon?

thirty sixImproved Answer:-Providing that it's a regular pentagon then each interior angle will measure 108 degrees


What is the size of one exterior angle in a regular hexagon?

Each exterior angle is 360/6 = 60 degrees


What is the size of one interior angle in a regular octagon?

135 degrees and its exterior angle is 45 degrees


A regular polygon an exterior angle of 30 What is the size of the interior angle?

Exterior angles are supplementary with interior angles, so 180-30=150


What is the size of each angle in a regular 25 sided shape?

Exterior angle = 14.4 degrees Interior angle = 165.6 degrees


What is the size of an interior angle of a 20 sided regular polygon?

exterior angle = 360° ÷ 20 sides = 18° interior angle = 180° - exterior angle = 180° - 18° = 162°


What is the measure of an interior angle of a regular pentagon rounded to the nearest tenth?

To the nearest tenth, the interior angle of a regular pentagon is 108.0o In a regular pentagon, the sum of the interior angles is (5 - 2) x 1800 = 3 x 1800 = 540o In a regular pentagon, the interior angles are all the same size and are 5400 ÷ 5 = 108o which to the nearest tenth is 108.0o


What are the size of exterior angles of hexagon?

Providing that it is a regular 6 sided hexagon then each exterior angle measures 60 degrees


What is the size of each interior angle of a regular polygon with 28 sides?

The easiest way to calculate this is to calculate the exterior angle and use the fact that the exterior and interior angles are supplementary. Sum exterior angles = 360° → Each exterior angle of a regular 28-agon is 360° ÷ 28 → Each interior angle of a regular 28-agon = 180° - 360° ÷ 28 = 167 1/7° ≈ 167.14°