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Q: What is the slope for the equation 3x - 2y 8?
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Is 3x plus 2y equals 8 a quadratic function?

3x + 2y = 8 2y=8-3x y=4-1.5x A quadratic has x^2 This is the equation of a line with negative slope.


What is the slope of the equation 2y equals 6x minus 8?

2y = 6x - 8y = 3x - 4========m(slope) = 3=========


What is 3x plus 2y equals 8?

3x + 2y = 8 This is an equation. It could be the equation of a line.


-3x plus 2y equals 8 in slope intercept form?

-3x + 2y = 8To get into slope intercept, we must set the equation equal to y2y = 3x + 8y = 3/2x + 8/2y = 3/2x + 4


What is 3x-2y equals 16 in slope intercept form?

The slope-intercept form of the equation of a line is y = mx + b, where m is the slope and b is the y-intercept. To put 3x - 2y = 16 in slope-intercept form just requires a little rearranging: 3x - 2y = 16 -2y = -3x + 16 (subtract 3x from both sides) y = 3/2x - 8 (divide all terms by -2) Now the equation is in slope-intercept form. The slope m is 3/2; the y-intercept is -8.


What is the slope intercept of 3x-2y equals -16?

3X - 2Y = - 16 - 2Y = - 3X - 16 Y = (3/2)X + 8 ==============slope intercept form


What is 3x 2y equals 16 in slope intercept form?

If you mean: 3x+2y = 16 then it is y = -1.5x+8


What is -3x plus 2y8?

If you mean the straight line equation of: -3x +2y = 8 then y = 1.5x +4 whereas as 1.5 is the slope and 4 is the y intercept


What equation represents the line perpendicular to 2y equals -6x plus 8 if the y-intercept is 5?

2y=-6x+8 Divide both sides by two y=-3x+4 -3 is the slope. to find the perpendicular slope it is the opposite reciprocal. This is means that 1/3 must be the new slope. So the answer is: y=1/3x+5


What is the slope-intercept form of 3x-2y equals -16?

y = 1.5x+8 So the slope is 1.5 and the intercept is 8


What is the slop of the function -6x-2y equal 8?

-6x-2y = 8 -2y = 6x+8 y = -3x-4 Therefore the slope is -3 and the y intercept is -4


What equation that represents the line perpendicular to 2y equals -6x plus 8 if the y-intercept is 5?

Let 'y' be the first equation and 'z' be the perpendicular one. 2y = -6x + 8 y = -3x + 4 A slope is perpendicular to another slope if and only if its slope is a negative reciporical of that slope. So z = x/3 + b and we know that b = 5, so z = x/3 + 5