If you mean: y+3 = -4(x-5) then y = -4x+17 whereas the slope of the line is -4 and the y intercept is 17
There is a standard equation for a straight line. It is y = mx + b. m is the slope and b is the y-intercept (when x = 0). In the question m = -4 and is therefore the slope of the line represented by the equation y = -4x + 7.
x - 4y = 3 is the slope of a line perpendicular to line whose equation is y -5 3x plus 8 3.
If you mean: y = mx+b then the slope of the line is m and the y intercept is b
4x-y+3 = 0 -y = -4x-3 y = 4x+3 Therefore: the slope is 4 and the y intercept is 3
The graph of the equation is a straight line. 'm' is its slope. 'b' is its y-intercept
q2
-4
5 and the y intercept is 2
There is a standard equation for a straight line. It is y = mx + b. m is the slope and b is the y-intercept (when x = 0). In the question m = -4 and is therefore the slope of the line represented by the equation y = -4x + 7.
what is the slope of the line that has the equation 4x+2y=12?
4x+2y = 6 2y = -4x+6 y = -2x+3 Slope = -2
The equation for the line is y = mx +b the slope is the value of m For example if y = 3x +4 the that is the equation that completely defines the line; its slope is 3
It is -a/b
The slope of the line that represents the graph of that equation is 15.
the slope will be positive 1.5x the whole equation is y=4.5+1.5x
y = mx + c is the equation of a straight oblique line where m = gradient The gradient is a measue of the steepness of a line (or a measure of the slope of the line)
x - 4y = 3 is the slope of a line perpendicular to line whose equation is y -5 3x plus 8 3.