Study guides

☆☆

Q: What is the smallest number that when divided by 5 is a remainder of 2?

Write your answer...

Submit

Still have questions?

Related questions

24

62 is the smallest number that leaves a remainder of 2 when divided by 3, 4, 5, and 6.

24

It is 30.

It is: 12

12

Smallest prime factor = smallest prime number which can be divided into the given number with no remainder 82/2=41, both 2 and 41 are prime and 2 is the smallest.

The answer is 1. The smallest prime is 2 and the greatest prime (of however many digits) must be odd. The remainder of ANY odd number when divided by 2 must be 1.

The smallest number that can be divided by 2 3 4 5 6 7 8 and always give you a remainder of 1 is 841

5. To leave a remainder of 1 when divided by 2, the number must be odd. To leave a remainder of 2 when divided by 3, the number must also be two more than a multiple of 3. The multiples of 3 which are odd are 1 x 3, 3 x 3, 5 x 3, etc. The smallest odd multiple of three is 1 x 3 = 3 ⇒ required number is 3 + 2 = 5.

59

29

People also asked