Not if you divide correctly.
Yes, 928 is divisible by two because it is an even number. A number is divisible by two if it can be divided evenly by 2 without leaving a remainder. In this case, 928 divided by 2 equals 464, which is a whole number without any remainder, confirming that 928 is indeed divisible by two.
The number that can go into both 28 and 100 is 4. This is because 28 divided by 4 equals 7 with no remainder, and 100 divided by 4 equals 25 with no remainder. Therefore, 4 is a common factor of both 28 and 100.
36 36 is 6 squared. 6 times 6. 36 divided by 2 is 18 36 divided by 3 is 12
Not evenly because it will have a remainder of 1
2 divided by 5 is 0.4
62 is the smallest number that leaves a remainder of 2 when divided by 3, 4, 5, and 6.
It is 30.
24
12
Smallest prime factor = smallest prime number which can be divided into the given number with no remainder 82/2=41, both 2 and 41 are prime and 2 is the smallest.
The answer is 1. The smallest prime is 2 and the greatest prime (of however many digits) must be odd. The remainder of ANY odd number when divided by 2 must be 1.
The smallest number that can be divided by 2 3 4 5 6 7 8 and always give you a remainder of 1 is 841
5. To leave a remainder of 1 when divided by 2, the number must be odd. To leave a remainder of 2 when divided by 3, the number must also be two more than a multiple of 3. The multiples of 3 which are odd are 1 x 3, 3 x 3, 5 x 3, etc. The smallest odd multiple of three is 1 x 3 = 3 ⇒ required number is 3 + 2 = 5.
169 is the smallest such number.
59
29
The smallest number that leaves a remainder of 2 when divided by 3, 4, 5 or 6 is 62. This can be found by analyzing the multiples of the greatest common divisor (GCD) of 3, 4, 5, and 6, which is 60. Adding 2 to this number gives us the smallest number with the specified remainder.