2 and 3 are the smallest prime numbers. So answer is 2^3 * 3^3 = 216
216
Just multiply the first three prime numbers together.
Just multiply the two smallest prime numbers. That's your number.
I think that it is 4
It is 2 × 3 × 5 × 7 × 11 = 2310
6666
Logically, the smallest number with 4 different prime factors would have to be the product of the smallest four prime numbers. So the smallest natural number with four different prime factors is 210 (2*3*5*7).
36
There isn't one. Negative numbers have prime factors and numbers don't stop. The smallest positive numbers with a prime factor is 2.
The smallest prime factors are 2,3,5,7 thus the smallest number would be the product of these will be 210
Just multiply the first three prime numbers together.
Square numbers have an odd number of factors.
360,360
The first prime numbers are 2, 3, 5, 7, 11. When multiplied together the product is 2310. It is the smallest number that has the first five numbers as its factors.
The smallest possible number to get from 3 and 4 as your factors is 12...
Just multiply the first five prime numbers! 2x3x5x7x11 = 6x35x11 = 210x11 = 2310. Any multiple of this number "has the first five prime numbers as factors", but 2310 is the smallest such number.
Just multiply the two smallest prime numbers. That's your number.
1024 has exactly eleven. 60 has twelve, so it has eleven as well.