It is 8y^2.
Square roots of square roots. The fourth root of a number, x, is another number, y such that y*y*y*y = x ie y multiplied by itself 4 times is x.
log of the square root of 'y' = 1/2 sqrt(y)
y6
5x times the square root of y
2x square root 6x y squared
If x equals the square root of ...., then you already have solved for x
Square roots of square roots. The fourth root of a number, x, is another number, y such that y*y*y*y = x ie y multiplied by itself 4 times is x.
square root (y) / Square root (3) root (y) / 1.73
x=y
log of the square root of 'y' = 1/2 sqrt(y)
y6
5x times the square root of y
X^1/2 + Y^1/2 Essentially it is just the square root of x plus the square root of y, there's no real way of simplifying that.
If x is a multiplication symbol, then square root of 36(4)y^2 = square root of(4^2)(2^2)(y^2) = (4)(2)(y) = 8y If it is a variable x, then square root of 36x4y^2 = square root of (4^2)(x)(2^2)(y^2) = (4)(2)(y)(square root of x)= 8y(square root of x)
2x square root 6x y squared
Algebraically if we have a number 'x^2' Then its square is (x^2)^2 = x^4 For the square root of x^2 = +/-x
y2