Square roots of square roots. The fourth root of a number, x, is another number, y such that y*y*y*y = x ie y multiplied by itself 4 times is x.
log of the square root of 'y' = 1/2 sqrt(y)
y6
5x times the square root of y
2x square root 6x y squared
If x equals the square root of ...., then you already have solved for x
Square roots of square roots. The fourth root of a number, x, is another number, y such that y*y*y*y = x ie y multiplied by itself 4 times is x.
square root (y) / Square root (3) root (y) / 1.73
x=y
log of the square root of 'y' = 1/2 sqrt(y)
y6
5x times the square root of y
If x is a multiplication symbol, then square root of 36(4)y^2 = square root of(4^2)(2^2)(y^2) = (4)(2)(y) = 8y If it is a variable x, then square root of 36x4y^2 = square root of (4^2)(x)(2^2)(y^2) = (4)(2)(y)(square root of x)= 8y(square root of x)
Oh, dude, the square root of x plus the square root of y is just that - the square root of x plus the square root of y. It's like adding apples and oranges, you can't really simplify it further. So, like, that's your answer, no need to overcomplicate things, man.
2x square root 6x y squared
Algebraically if we have a number 'x^2' Then its square is (x^2)^2 = x^4 For the square root of x^2 = +/-x
y2