11,450
100000
No. If a number is divisible by three, the sum of its digits will be divisible by three. Obviously, the sum of the digits of 10000 is 1, and 1 is not divisible by 3, so 10000 is not divisible by 3.
This is easiest to answer by summing all the numbers 1-10000 and subtracting the sum of the multiples of 7 (7, 14, 21, ..., 9996). The sum of a series is: S = (first + last) x number_of_terms / 2 For for 1-10000, the sum is: S1 = (1 + 10000) x 10000 / 2 = 10001 x 5000 = 50005000 For the multiples of 7 the sum is: S2 = (7 + 9996) x 1428 / 2 = 10003 x 714 = 7142142 So the sum of all integers not greater than 10000 that are not divisible by 7 is: S = S1 - S2 = 50005000 - 7142142 = 42,862,858
The sum of the first 10,000 even numbers is 100,010,000.
Their sum is 10000.
Sum(not div by 7) = Sum(all) - Sum(div by 7) Now the sum of an AP is Sn = n/2 (first + last) where n is the number of terms Sum(All) = 10000/2 (1 + 10000) = 50005000 Sum(div by 7) = (9996/7)/2 (7 + 9996) = 1428/2 (10003) = 7142142 Sum(not div by 7) = Sum(all) - Sum(div by 7) = 50005000 - 7142142 = 42 862 858
It is 100^2=10000
200*50=10000
342 of them.
22 percent of 1450 = 31922% of 1450=22% * 1450= 0.22 * 1450= 319
120% of 1450 = 120% * 1450 = 1.2 * 1450 = 1740
The sum of the first 100 odd numbers (1 through 199) is 10000 (ten thou)