10000 x 8000 = 80000000
(4+5) - (2 x 3) = 3
10000 x 7000000 = 70000000000
the sum equals x+10
0.25 x 0.2 x 0.5 x 10000 = 250
This is easiest to answer by summing all the numbers 1-10000 and subtracting the sum of the multiples of 7 (7, 14, 21, ..., 9996). The sum of a series is: S = (first + last) x number_of_terms / 2 For for 1-10000, the sum is: S1 = (1 + 10000) x 10000 / 2 = 10001 x 5000 = 50005000 For the multiples of 7 the sum is: S2 = (7 + 9996) x 1428 / 2 = 10003 x 714 = 7142142 So the sum of all integers not greater than 10000 that are not divisible by 7 is: S = S1 - S2 = 50005000 - 7142142 = 42,862,858
10,000,000,000,000,000
37,594 in expanded notation as the sum of multiplication expressions is: (3 x 10000) + (7 x 1000) + (5 x 100) + (9 x 10) + (4 x 1)
11,450
No. If a number is divisible by three, the sum of its digits will be divisible by three. Obviously, the sum of the digits of 10000 is 1, and 1 is not divisible by 3, so 10000 is not divisible by 3.
10,000 x 10,000 = 100,000,000
10000 x 8000 = 80000000
10000 x 10000 = 100 000 000 Trees
(4+5) - (2 x 3) = 3
The sum of the first 10,000 even numbers is 100,010,000.
Their sum is 10000.
Sum(not div by 7) = Sum(all) - Sum(div by 7) Now the sum of an AP is Sn = n/2 (first + last) where n is the number of terms Sum(All) = 10000/2 (1 + 10000) = 50005000 Sum(div by 7) = (9996/7)/2 (7 + 9996) = 1428/2 (10003) = 7142142 Sum(not div by 7) = Sum(all) - Sum(div by 7) = 50005000 - 7142142 = 42 862 858