The integers would begin with 10.
They are 14, 16 and 18.
The let statement is: let the smallest of the three integers be x.
-1, 1 and 3
5*x = 4*(x+2) + 3 so 5x = 4x + 8 + 3 = 4x + 11 Subtracting 4x from both sides: x = 11 So the two integers are 11 and 13.
One possible answer is -4 and -3.
The sum of three consecutive integers is -72
They are 14, 16 and 18.
10-11-12
The numbers are 14, 16 and 18.
The let statement is: let the smallest of the three integers be x.
The integers are 5 and 7.
9,11,13
-1, 1 and 3
5*x = 4*(x+2) + 3 so 5x = 4x + 8 + 3 = 4x + 11 Subtracting 4x from both sides: x = 11 So the two integers are 11 and 13.
One possible answer is -4 and -3.
There can be no such integers: a smaller integer cannot be 5 times the larger number.
Suppose the middle integer is a. Then the three consecutive integers are a-1, a and a+1. Now, 3*a = (a-1)+(a+1) + 1 So 3a = 2a + 1 => a=1 So the three numbers are 0, 1 and 2