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The sum of 3 consecutive even integers is 54 What is the first consecutive integer?
The first integer is 17.
Find three consecutive integers such that three times the middle integer is one more than the sum of the first and third?
Suppose the middle integer is a. Then the three consecutive integers are a-1, a and a+1. Now, 3*a = (a-1)+(a+1) + 1 So 3a = 2a + 1 => a=1 So the three numbers are 0, 1 and 2
What is the sum of four consecutive even integers is 2 more than five times the first integer?
The integers would begin with 10.
How Find three consecutive even integers such that three times the first integer i six more than twice the second integer?
They are 14, 16 and 18.
What are two consecutive integers whose sum is 24?
There are no two such consecutive 'integers'!!Proof: Let the first integer be x.So, the next consecutive integer is x+1.Now, as per the question : x + (x+1) = 24=> 2x=23 (After taking all constants on one side and variable terms on the other).=> x=(23/2) = 11.5So, 11.5 & 12.5 are the required numbers but they are not integers !
The sum of 3 consecutive even integers is 54 What is the first consecutive integer?
The first integer is 17.
Find three consecutive integers such that three times the middle integer is one more than the sum of the first and third?
Suppose the middle integer is a. Then the three consecutive integers are a-1, a and a+1. Now, 3*a = (a-1)+(a+1) + 1 So 3a = 2a + 1 => a=1 So the three numbers are 0, 1 and 2
The sum of 4 consecutive integers is 182 What is the first integer?
Oh, isn't that a happy little math problem! To find the first integer, you can use a simple formula. Since the sum of 4 consecutive integers is 182, you can divide 182 by 4 to find the average value of the integers. Then, you can work backwards to find the first integer. Just remember, there are no mistakes in math, only happy little accidents!
Find 2 consecutive integers whose difference is 2?
no solution. If you solve for x (where x is the first integer) the answer is a fraction, which is not an integer.
What is the sum of four consecutive even integers is 2 more than five times the first integer?
The integers would begin with 10.
Find four consecutive integers such that the sum of the second and fourth is 132 show the work?
Let the first consecutive integer be x. So that:the second integer is x + 1,the third integer is x + 2, andthe fourth integer is x + 3.We have:(x + 1) + (x + 3) = 1322x + 4 = 1322x = 128x = 64 the first integerThus, the four consecutive integers are 64, 65, 66, and 67.
How Find three consecutive even integers such that three times the first integer i six more than twice the second integer?
They are 14, 16 and 18.
What three consecutive positive even integers such that the product of the second and third integers is twenty more than ten times the first integer?
10-11-12
How Find three consecutive even integers such that three times the first integer is six more than twice the second integer?
The numbers are 14, 16 and 18.
The sum of two consecutive integers is 15?
Let the first integer be x. The second consecutive integer would then be x+1. The sum of these two integers is x + (x+1) = 15. Simplifying, we get 2x + 1 = 15. Solving for x, we find that x = 7. Therefore, the two consecutive integers are 7 and 8.
What is the sum of 3 even consecutive integers if the first integer is y?
y, y+2, y+4
What are two consecutive integers whose sum is 24?
There are no two such consecutive 'integers'!!Proof: Let the first integer be x.So, the next consecutive integer is x+1.Now, as per the question : x + (x+1) = 24=> 2x=23 (After taking all constants on one side and variable terms on the other).=> x=(23/2) = 11.5So, 11.5 & 12.5 are the required numbers but they are not integers !
