Q: What is the sum of the first 50 terms of the sequence an equals 3n plus 2?

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2,1,0 is th sequence of its terms

9, 10, 11 and 12

9, 17, 25, 33, 41

5, 8, 11, 14 and 17.

That equals x.

then 4 plus 3 equals 28 and 3 plus 3 equals 18 and 7 plus 5 equals 84 .... its easy you just have to multiply the answer with the first number.. for example : 2 plus 3 equals 5 but when you multiply the answer with the first number (2) it becomes equals 10, and so on the others..

is a quadratic equation for y, in terms of x.

144, you add the plus numbers, then multiply it by the first.

144, you add the plus numbers, then multiply it by the first.

Answer: 144Logic: Product of first number and sum of two numbers2+3 =10; 2*(2+3)7+2=63; 7*(7+2).....9+7=? 9*(9+7)= 9*16 = 144

Sinθ plus cosθ2 plus sinθ-cosθ2 equals 2 does not equal 2. It equals 2sinθ. The cosθ2 terms cancel out and you are left with sinθ + sinθ which is 2sinθ.

5p + 4y

12+7=8, 22+7=11, 32+7=16, 42+7=23

Starting from 1, your get: [4n + 5] = 9, 13, 17, 21, 25 Basically you find the first one and add 4 each time.

In mathematical terms, the question is misguided because one plus one IS NOT one.

19, 38, 57, 76, or 95

Gathering like terms together, this is equal to 5a + 3b + 7c.

Because all the terms have been divided by -1

By listed sequence, it is 5 plus 10 = 15 divided by 5 equals 3. By order of operations, it is 5 + (10/5) = 5 + 2 equals 7.

2048

first combine like terms and 5n+7=-41 add -7 to both sides 5n=-48 n=-48/5

I think no. IT is impossible

Because you cannot combine terms that are not alike.

2 and 3

42

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