0
Assuming you mean -90 degrees, not radians:
tan (-90) = [sin(-90)]/[cos(-90)] = (-1) / 0
You cannot divide by zero. tan (-90) is undefined/does not exist.
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∙ 14y ago
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In Triangle ABC what is the value of Tan A by 2 in terms of its sides if angle B is 90 degrees?
If B is 90 degrees, Tan A is BC / AB. But I don't know what you mean by Tan A by 2.
Why tan A 90 degree is not solve?
I am not sure what "tan A 90 degree" means. tan(90 degrees) is an expression that is not defined and so cannot be solved. One way to see why that may be so is to think of tan(x) = sin(x)/cos(x). When x = 90 degrees, sin(90) = 1 and cos(90)= 0 that tan(90) = 1/0 and since division by 0 is not defined, tan(90) is not defined.
What is tan x degree 90?
To solve for tan x degree 90 you do a few things. First, if x equals 90, then this equals 1.5597 radian or 89.36 degrees. This is the easiest way to solve tan x degree 90.
Tan 90 degree?
It is not defined.
By using trigonometric identities find the value of sin A if tan A a half?
The value of tan A is not clear from the question.However, sin A = sqrt[tan^2 A /(tan^2 A + 1)]
How do you find the value of tan 135?
tan(135) = -tan(180-135) = -tan(45) = -1
What is tan20tan32 plus tan32tan38 plus tan38tan20?
This may not be the most efficient method but ... Let the three angle be A, B and C. Then note that A + B + C = 20+32+38 = 90 so that C = 90-A+B. Therefore, sin(C) = sin[(90-(A+B) = cos(A+B) and cos(C) = cos[(90-(A+B) = sin(A+B). So that tan(C) = sin(C)/cos(C) = cos(A+B) / sin(A+B) = cot(A+B) Now, tan(A+B) = [tan(A)+tan(B)] / [1- tan(A)*tan(B)] so cot(A+B) = [1- tan(A)*tan(B)] / [tan(A)+tan(B)] The given expressin is tan(A)*tan(B) + tan(B)*tan(C) + tan(C)*tan(A) = tan(A)*tan(B) + [tan(B) + tan(A)]*cot(A+B) substituting for cot(A+B) gives = tan(A)*tan(B) + [tan(B) + tan(A)]*[1- tan(A)*tan(B)]/[tan(A)+tan(B)] cancelling [tan(B) + tan(A)] and [tan(A) + tan(B)], which are equal, in the second expression. = tan(A)*tan(B) + [1- tan(A)*tan(B)] = 1
What is the value of tan 22.5 degrees?
tan(22.5)=0.414213562
What is the limit of arc tan?
The principal range of arc tan is an angle in the open interval (-pi/2, pi/2) radians = (-90, 90) degrees.
What is tan of 90 degrees?
On the unit circle at 90 degrees the 90 degrees in radians is pi/2 and the coordinates for this are: (0,1). The tan function = sin/cos. In the coordinate system x is cos and y is sin. Therefore (0,1) ; cos=0, & sin=1 . Tan=sin/cos so tan of 90 degrees = 1/0. The answer of tan(90) = undefined. There can not be a 0 in the denominator, because you can't devide by something with no quantity. Something with no quantity is 0. Or, on a limits point of view, it would be infinity.
What is the value of the tan of 42 degrees?
Tan 42 degrees = 0.9004
What is the value of the tan of 61 degrees?
tan(61°) = 1.80405 (rounded)
