To find the vertex of the quadratic equation ( y = x^2 - 8x - 3 ), we can use the vertex formula ( x = -\frac{b}{2a} ). Here, ( a = 1 ) and ( b = -8 ), so ( x = -\frac{-8}{2 \cdot 1} = 4 ). Plugging ( x = 4 ) back into the equation gives ( y = 4^2 - 8 \cdot 4 - 3 = 16 - 32 - 3 = -19 ). Thus, the vertex is at the point ( (4, -19) ).
Do you have a specific vertex fraction? vertex = -b/2a wuadratic = ax^ + bx + c
2 AND 9
It is (1, 1).
y=2(x-3)+1
No.
it is a vertices's form of a function known as Quadratic
It if the max or minimum value.
The vertex.
vertex
Do you have a specific vertex fraction? vertex = -b/2a wuadratic = ax^ + bx + c
The vertex form for a quadratic equation is y=a(x-h)^2+k.
2 AND 9
You should always use the vertex and at least two points to graph each quadratic equation. A good choice for two points are the intercepts of the quadratic equation.
The graph of a quadratic function is always a parabola. If you put the equation (or function) into vertex form, you can read off the coordinates of the vertex, and you know the shape and orientation (up/down) of the parabola.
D
It is (1, 1).
No.