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To find the vertex of the quadratic equation ( y = x^2 - 8x - 3 ), we can use the vertex formula ( x = -\frac{b}{2a} ). Here, ( a = 1 ) and ( b = -8 ), so ( x = -\frac{-8}{2 \cdot 1} = 4 ). Plugging ( x = 4 ) back into the equation gives ( y = 4^2 - 8 \cdot 4 - 3 = 16 - 32 - 3 = -19 ). Thus, the vertex is at the point ( (4, -19) ).

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1w ago

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