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The vertex form for a quadratic equation is y=a(x-h)^2+k.

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What is the vertex form of y -4x2-6x?

The question does not contain an equation: only an expression. An expression cannot have a vertex form.


What different information do you get from vertex form and quadratic equation in standard form?

The graph of a quadratic function is always a parabola. If you put the equation (or function) into vertex form, you can read off the coordinates of the vertex, and you know the shape and orientation (up/down) of the parabola.


What is the difference between standard form and vertex form?

The difference between standard form and vertex form is the standard form gives the coefficients(a,b,c) of the different powers of x. The vertex form gives the vertex 9hk) of the parabola as part of the equation.


How do you write y equals x minus 4 x plus 2 in vertex form and find the vertex?

The given equation is y = x - 4x + 2 which can be written as y = -3x + 2 This is an equation of a straight line. Therefore it has no vertex and so cannot be written in vertex form.


The vertex of the parabola below is at the point (-4-2) which equation below could be one for parabola?

-2


What is an equation of the parabola in vertex form that passes through (13 8) and has vertex (3 2).?

please help


How do you find the vertex of an equation in standard form?

To find the vertex of a quadratic equation in standard form, (y = ax^2 + bx + c), you can use the vertex formula. The x-coordinate of the vertex is given by (x = -\frac{b}{2a}). Once you have the x-coordinate, substitute it back into the equation to find the corresponding y-coordinate. The vertex is then the point ((-\frac{b}{2a}, f(-\frac{b}{2a}))).


What is a quadratic equation in vertex form for a parabola with vertex (11 -6)?

A quadratic equation in vertex form is expressed as ( y = a(x - h)^2 + k ), where ((h, k)) is the vertex of the parabola. For a parabola with vertex at ((11, -6)), the equation becomes ( y = a(x - 11)^2 - 6 ). The value of (a) determines the direction and width of the parabola. Without additional information about the parabola's shape, (a) can be any non-zero constant.


What is the formula for quadratic equation in vertex form?

y=2(x-3)+1


How do you find the vertex of an equation in vertex form?

look for the interceptions add these and divide it by 2 (that's the x vertex) for the yvertex you just have to fill in the x(vertex) however you can also use the formula -(b/2a)


The vertex of the parabola below is at the point (5 -3). Which of the equations below could be the one for this parabolaus anything?

To determine the equation of a parabola with a vertex at the point (5, -3), we can use the vertex form of a parabola's equation: (y = a(x - h)^2 + k), where (h, k) is the vertex. Substituting in the vertex coordinates, we have (y = a(x - 5)^2 - 3). The value of "a" will determine the direction and width of the parabola, but any equation in this form with varying "a" values could represent the parabola.


What is the standard form of the equation of the parabola with vertex 00 and directrix y4?

Assuming the vertex is 0,0 and the directrix is y=4 x^2=0