y=2(x-3)+1
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To find the vertex of a quadratic equation in standard form, (y = ax^2 + bx + c), you can use the vertex formula. The x-coordinate of the vertex is given by (x = -\frac{b}{2a}). Once you have the x-coordinate, substitute it back into the equation to find the corresponding y-coordinate. The vertex is then the point ((-\frac{b}{2a}, f(-\frac{b}{2a}))).
Put the quadratic equation into standard form; identify the coefficients (a, b, c), replace them in the equation, do the calculations.
A quadratic equation in its general form of ax2+bx+c = 0 whereas 'a' is equal or greater than 1 is applicable when finding the unknown variable of x by using the quadratic equation formula.
The quadratic equation in standard form is: ax2 + bx + c = 0. The solution is x = [-b ± √b2- 4ac)] ÷ 2a You can use either plus or minus - a quadratic equation may have two solutions.
Do you have a specific vertex fraction? vertex = -b/2a wuadratic = ax^ + bx + c