use pythagorean theorem where a2+b2=c2
(w+2)2+w2=102
2w2+4x+4=100
2w2+4x-96=0
divide by 2
w2 +2x-96=0
factor it
(w-6)(w+8)0
you're answer is 6 centimeters because it can't be negative
lol i posted this question and then figured it out :D
Using Pythagoras' theorem it works out as 194.9820505 or 195 centimeters
To find the length of a diagonal in a rectangle, use the Pythagorean method. Diagonal length = square root(length squared + height squared).
The diagonal is 26cm
Diagonal = 17 cm and height = 8 cm so Length = sqrt[172 - 82] = sqrt(225) = 15 cm Then area = length*height = 15*8 = 120 cm2
The diagonal length is about 18.44 inches.
15 cm for the diagonal.
The simplest Pythagorean triangle is 3, 4 and 5. Double this gives 6, 8 and 10 so the sides of your rectangle are 6 cm & 8 cm.
64 centimetres.
The answer depends on what information you have about the rectangle: the area and width, or width and diagonal, area and perimeter or some other measures.
The diagonal is 7.21 feet.
Using Pythagoras' theorem it works out as 194.9820505 or 195 centimeters
To find the length of a diagonal in a rectangle, use the Pythagorean method. Diagonal length = square root(length squared + height squared).
The length of the diagonal is about 16.03 feet.
-- A rectangle has no 'formula'. -- The length of the diagonal is 24feet 10.62inches (rounded)
The diagonal is 26cm
Diagonal = 17 cm and height = 8 cm so Length = sqrt[172 - 82] = sqrt(225) = 15 cm Then area = length*height = 15*8 = 120 cm2
The diagonal length is about 18.44 inches.