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3x + 4y = 12 subtract 3x to both sides
4y = -3x + 12 divide by 4 to both sides
y = (-3/4)x + 3 directly we say that y-intercept is 3, to find x-intercept assigning y to 0;
0 = (-3/4)x + 3
-3 = (-3/4)x multiply by -4/3 to both sides
(-3)(-4/3) = (-3/4)(-4/3)x
4 = x the x-intercept is 4
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What is the x and y intercept of 3x plus 4y12?
If you mean 3x+4y = 12 then the x intercept = 4 and the y intercept = 3
Find the x-intercept and y-intercept of y equals -3x - 5?
-8
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5
What are the coodinates of the x intercept and y intercept of this linear 3x-4y equals 24?
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3x - 5y = 45At the y-intercept, x = 0.-5y = 45y = -9At the x-intercept, y = 0.3x = 45x = 15
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What is the x and y intercepts of -3x plus 5y equals -15?
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What are the x and y intercepts of the problem 3x plus y equals 12?
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What is the x intercept of -5y plus 3x equals 12?
X intercept is the value of X when Y = 0 -5Y + 3X = 12 ley Y = 0 3x = 12 x = 4
What is the x-intercept of y equals -3x-5?
2
What is x and y intercepts to -3x 5y30?
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