If you mean: -3x+5y = 30 then the x intercept is at (-10, 0) and the y intercept is at (0, 6)
X intercept: -5 Y intercept: +3
x=20 y=-3
Since this is not put into an equation form(there is no =) it cannot be determined by this. Add the equal sign where it needs to be and I'll answer for you.
the y intercept occurs when x=0 y=3(0) -2 y=-2 the x intercept occurs when y=0 0=3x-2 2=3x x=2/3=.667
To find the intercepts of the line represented by the equation (3x + 4y - 12 = 0), we can rearrange it into slope-intercept form. The x-intercept occurs when (y = 0): setting (4y = 12 - 3x) gives (x = 4) (intercept at (4,0)). The y-intercept occurs when (x = 0): setting (3x = 12 - 4y) gives (y = 3) (intercept at (0,3)). Thus, the intercepts are (4, 0) and (0, 3).
Given the linear equation 3x - 2y^6 = 0, the x and y intercepts are found by replacing the x and y with 0. This gives the intercepts of x and y where both = 0.
X intercept: -5 Y intercept: +3
They are at: x = -2.5 and x = 4
The question does not contain an equation (or inequality) but an expression. An expression cannot have intercepts.
They are: 6 and -3
-3x + 5y = -15At the x-intercept, y=0:-3x = -15 . . . . . x = 5At the y-intercept, x=0:5y = -15 . . . . . y = -3
x=20 y=-3
3x + y = 12The x intercept occurs when y = 0. Then, 3x + 0 = 12 : 3x = 12 : x = 4The y intercept occurs when x = 0. Then, (3 x 0) + y = 12 : y = 12.
Assuming the equation is 3x + y = 15, then the x-intercept is (5, 0) and the y-intercept is (0, 15).
x intercept = 5 y intercept = 15
0
Since this is not put into an equation form(there is no =) it cannot be determined by this. Add the equal sign where it needs to be and I'll answer for you.