If you mean: -3x+5y = 30 then the x intercept is at (-10, 0) and the y intercept is at (0, 6)
X intercept: -5 Y intercept: +3
x=20 y=-3
To find the intercepts of the equation (3xy = 15), we first rewrite it as (y = \frac{15}{3x} = \frac{5}{x}). The x-intercept occurs when (y = 0), which does not exist for this equation since (y) is undefined when (x = 0). For the y-intercept, we set (x = 0), but again, this results in division by zero, indicating there is no y-intercept either. Therefore, the graph has no x- or y-intercepts.
Since this is not put into an equation form(there is no =) it cannot be determined by this. Add the equal sign where it needs to be and I'll answer for you.
To find the x-intercepts of the graph of the equation ( y = -3x^2 + 4x ), set ( y ) to zero: [ 0 = -3x^2 + 4x. ] Factoring gives: [ 0 = x(-3x + 4). ] This results in two solutions: ( x = 0 ) and ( -3x + 4 = 0 ) (which gives ( x = \frac{4}{3} )). Therefore, the x-intercepts are ( x = 0 ) and ( x = \frac{4}{3} ).
Given the linear equation 3x - 2y^6 = 0, the x and y intercepts are found by replacing the x and y with 0. This gives the intercepts of x and y where both = 0.
X intercept: -5 Y intercept: +3
They are at: x = -2.5 and x = 4
The question does not contain an equation (or inequality) but an expression. An expression cannot have intercepts.
They are: 6 and -3
-3x + 5y = -15At the x-intercept, y=0:-3x = -15 . . . . . x = 5At the y-intercept, x=0:5y = -15 . . . . . y = -3
3x + y = 12The x intercept occurs when y = 0. Then, 3x + 0 = 12 : 3x = 12 : x = 4The y intercept occurs when x = 0. Then, (3 x 0) + y = 12 : y = 12.
x=20 y=-3
Assuming the equation is 3x + y = 15, then the x-intercept is (5, 0) and the y-intercept is (0, 15).
To find the intercepts of the equation (3xy = 15), we first rewrite it as (y = \frac{15}{3x} = \frac{5}{x}). The x-intercept occurs when (y = 0), which does not exist for this equation since (y) is undefined when (x = 0). For the y-intercept, we set (x = 0), but again, this results in division by zero, indicating there is no y-intercept either. Therefore, the graph has no x- or y-intercepts.
Since this is not put into an equation form(there is no =) it cannot be determined by this. Add the equal sign where it needs to be and I'll answer for you.
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