its still 3x+x2
to add you must have same variable you would only be able to multiply these numbers to get 3x3 but they cannot be added
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x2 plus 3x plus 3 is equals to 0 can be solved by getting the roots.
x2 + 48x + 320
(x2+3x-4) (x-4)
x2 + 3x + 7 = 5 ∴ x2 + 3x + 2 = 0 ∴ (x + 1)(x + 2) = 0 ∴ x ∈ {-2, -1}
x2 + 3x - 40 = (x + 8)(x - 5)
3 - 3x + x2 - x3 = (1 - x)(x2 + 3)
x3 + x2 - 3x - 3 x(x2 + x - 3) - 3
(x2 + 3x + 5)(x2 - 3x + 4)
x2 + 3x + 2 factors into (x + 1) (x + 2)
3(x2 + 3x + 1)
The answer would be 3x if 'X2' is '2x', but if 'X2' is x2, then the total answer would be x2 + x.
X2+3x+x+3=x(x+1)+3(x+1)=(x+3)(x+1)