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x2 = 2x? Good question.
This problem is quite difficult to solve with normal functions. You could use a function called the Lambert W function to solve it, but that is beyond my understanding.
The three real solutions to the equation -- found numerically -- are -0.7666647, 2 and 4.
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How do you substitute x plus y equals 5 and x equals y plus 1?
Eq 1: + y= 5 Eq 2: x = y + 1 substitute y + 1 for x in equqtion 1 y+1 + y = 5 2y + 1 = 5 2 y = 4 y = 2 substitute 2 for y in eq 2 x = 2 + 1 x = 3
What is x-2y equals 0 in 4x-3y equals 15?
eq. 1 is x-2y=0 which means x=2y eq. 2 is 4x-3y=15 subst. x=2y in eq. 2 4(2y)-3y=15 8y-3y=15 5y=15 y=3 subst. y=3 in eq. 1 we get x=2(3) x=6 Ans: x=6 and y=3 is the required solution. Thank you.
The sum of two integers is 51 the larges integer is 3 more than twice the smaller integer find the integer?
Answer: 16 and 35 Solution: Suppose the integers are: x, y. and y is greater than x. x + y = 51 ................(eq. 1) y= 2 x + 3 ................(eq. 2) substitute eq. 2 in eq 1: x + 2 x + 3 = 51 3 x + 3 = 51 add -3 to both sides in last equation: 3 x = 51 - 3 3 x = 48 divide both sides by 3 in last line: 3 x/ 3 = 48 / 3 x = 16 substitute the value of x in eq. 2: y = 2 x + 3 y= 2 * 16 + 3 y = 35
When using substitution What is x and y for 3x plus 6y equals 48 -5x plus 6y equals 32?
3x + 6y = 48 .... Eq.1-5x + 6y = 32 .... Eq.2 .... in another way 6y = 5x + 32Put the value of Eq.2 in Eq. 13x + 5x + 32 = 488x = 48 - 328x = 16x = 16/8 ...... X = 2To find the value of Y put the value of X in Eq.26y = 5x + 326y = 5(2) + 326y = 10 + 326y = 42y = 42/6 ...... Y + 7
2x plus y equals 5 2y plus x equals 4?
2x + y = 5 2y + x = 4 This is SIMULTANEOUS Equations. To solve , arbitrarily select a letter to eliminate, In this case 'x' To do this the coefficients of 'x' must be the same , but of opposite sign. Hence multiply the bottom equation by '-2' Hence 2x + y = 5 -2x - 4y = =8 Add -3y = -3 Divide both sides by '-1' 3y = 3 y = 1 When y= 1 Substitute back in to either eq'n 2x + 1 = 5 Subtract '1' from both sides 2x = 4 x = 2 Hence the answer is ( x,y) = ( 2,1)
Which one is bigger 3.14 x 10 to the power of 99 3 x 10 to the power of 100?
3 x 10100 is greater than 3.14 x 1099. 3.14 x 1099 -----(Eq.1) 3 x 10100 -------(Eq.2) divide the two equations by 1099 Eq.1 = 3.14 Eq. 2 = 3 x 10 = 30 thus, 3 x 10100 is greater than 3.14 x 1099.
Solve the following system of equation algebraically 3xplus2y equals 4 4xplus 3y equals 7?
3x + 2y = 4 (Eq 1); 4x + 3y = 7 (Eq 2) Eliminate x Eq 1 x 4 = 12x + 8y = 16 (Eq 3) Eq 2 x 3 = 12x + 9y = 21 (Eq 4) Subtract Eq 3 from Eq 4 y = 5 so x = (4 - 10)/3 = -6/3 ie -2 Check Eq 2: (4 x -2) + (3 x 5) = -8 + 15 = 7 QED
How do you substitute x plus y equals 5 and x equals y plus 1?
Eq 1: + y= 5 Eq 2: x = y + 1 substitute y + 1 for x in equqtion 1 y+1 + y = 5 2y + 1 = 5 2 y = 4 y = 2 substitute 2 for y in eq 2 x = 2 + 1 x = 3
X plus 7y equals 39 and 3x minus 2y equals 2?
x + 7y = 39 ....... Eq.13x - 2y = 2 ....... Eq.2multiply Eq.1 with (-3) and so Eq.1 will be :-3x - 21y = -1173x - 2y = 2_________________ by Elimination method ( Eq.1 + Eq.2 ) the result will we :- 21y - 2y = - 115-23y = -115Y = 5to find the value of x, put the value of y in Eq.1 :x + 7y = 39x = 39 - 7yx = 39 - 7(5)X = 4___________________________________________________________you can solve it in another way by using substitution method:x + 7y = 39 ....... Eq.1 ,, you can write it in another form, x = 39 - 7y3x - 2y = 2 ....... Eq.2Put the value of Eq.1 on Eq.23(39 - 7y) - 2y = 2117 - 21y - 2y = 2117 - 23y = 223y = 115 ............ Y = 5to find the value of X , put the value of Y in Eq.1x = 39 - 7yx = 39 - 7(5)x = 39 - 35 .............. X = 4and so in both ways....you got the same answer choose the easiest way for you :)good luck my friend...
What is the solution for X plus 7y equals 39 and 3x-2y equals 2 is?
x + 7y = 39 ....... Eq.13x - 2y = 2 ....... Eq.2multiply Eq.1 with (-3) and so Eq.1 will be :-3x - 21y = -1173x - 2y = 2_________________ by Elimination method ( Eq.1 + Eq.2 ) the result will we :- 21y - 2y = - 115-23y = -115Y = 5to find the value of x, put the value of y in Eq.1 :x + 7y = 39x = 39 - 7yx = 39 - 7(5)X = 4___________________________________________________________you can solve it in another way by using substitution method:x + 7y = 39 ....... Eq.1 ,, you can write it in another form, x = 39 - 7y3x - 2y = 2 ....... Eq.2Put the value of Eq.1 on Eq.23(39 - 7y) - 2y = 2117 - 21y - 2y = 2117 - 23y = 223y = 115 ............ Y = 5to find the value of X , put the value of Y in Eq.1x = 39 - 7yx = 39 - 7(5)x = 39 - 35 .............. X = 4and so in both ways....you got the same answer choose the easiest way for you :)good luck my friend...
What is x-2y equals 0 in 4x-3y equals 15?
eq. 1 is x-2y=0 which means x=2y eq. 2 is 4x-3y=15 subst. x=2y in eq. 2 4(2y)-3y=15 8y-3y=15 5y=15 y=3 subst. y=3 in eq. 1 we get x=2(3) x=6 Ans: x=6 and y=3 is the required solution. Thank you.
Solve the simultaneous equations 4x plus 3y equals -5 3x plus 5y equals -12?
4x + 3y = -5 (Eq 1); 3x + 5y = -12 (Eq 2) Eliminate x Eq 1 times 3: 12x + 9y = -15 Eq 2 times 4: 12x +20y = -48 Subtract Eq 1 from Eq 2 11y = -48-(-15) ie 11y = -33 y = -3 Substitute in Eq 1: 4x - 9 = -5, ie 4x = 4 so x = 1 Check in Eq 2: (3 x 1) + (5 x -3) = 3 - 15 = -12. QED
How do you solve the system of equasions x y z-10 2x 4y 2z-32 and-x 8y-3z-42?
Assuming the equations are: x + y. + z = 10 1 2x + 4y + 2z =32 2 -x +8y - 3z = 42 3 Multiply eq 3 by 2 and add to eq 2: 20y -4z = 116 4 Multiply eq 1 by 2 and subtract it from eq 2: 2y = 12; then y = 6 Substitute in eq 4: Then -4z = 116 - 120 = -4; z = 1 Substitute in eq 1; then X = 10 - 6 - 1 = 3 Answer: X = 3 Y = 6 Z = 1
The sum of two integers is 51 the larges integer is 3 more than twice the smaller integer find the integer?
Answer: 16 and 35 Solution: Suppose the integers are: x, y. and y is greater than x. x + y = 51 ................(eq. 1) y= 2 x + 3 ................(eq. 2) substitute eq. 2 in eq 1: x + 2 x + 3 = 51 3 x + 3 = 51 add -3 to both sides in last equation: 3 x = 51 - 3 3 x = 48 divide both sides by 3 in last line: 3 x/ 3 = 48 / 3 x = 16 substitute the value of x in eq. 2: y = 2 x + 3 y= 2 * 16 + 3 y = 35
Use the substitution method to solve the system of equations Enter your answer as an ordered pair x plus y equals 10 y equals x - 6?
16
Find two numbers whose sum is 36 and such one is 3 times as large as the other?
x + y =36 eq.1 x = 3y eq.2 Substitute value of x (eq.2) to equation 1: 3y + y = 36 4y = 36 y=9 x = 3y x = 3(9) x = 27 from equation 1: x + y =36 27 + 9 = 36
When using substitution What is x and y for 3x plus 6y equals 48 -5x plus 6y equals 32?
3x + 6y = 48 .... Eq.1-5x + 6y = 32 .... Eq.2 .... in another way 6y = 5x + 32Put the value of Eq.2 in Eq. 13x + 5x + 32 = 488x = 48 - 328x = 16x = 16/8 ...... X = 2To find the value of Y put the value of X in Eq.26y = 5x + 326y = 5(2) + 326y = 10 + 326y = 42y = 42/6 ...... Y + 7
