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What else can I help you with?
How do you multiply when you have a x and y in polynomials and you have to multiply them?
x times y is "xy"
If x equals 0 and y equals 1 then xy equals?
If ( x = 0 ) and ( y = 1 ), then ( xy = 0 \times 1 = 0 ). Therefore, the value of ( xy ) is 0.
If x equals -8 and xy equals 1 what does y equal?
So far you know that: x=-8 xy=1 so xy means x times y. If you split xy. y=1/x or y=1/-8 1/-8= -0.125 You can find out that this is correct with the formula xy=1 because -0.125 x -8 is 1.
X plus XY equals 8 solve for Y?
x+xy=8 xy=-x+8 y=-1+8/x
If x4and y2 the value of xy squared?
To find the value of (xy^2) given (x = 4) and (y = 2), substitute the values into the expression. This gives (xy^2 = 4 \times (2^2) = 4 \times 4 = 16). Therefore, the value of (xy^2) is 16.
How do you multiply when you have a x and y in polynomials and you have to multiply them?
x times y is "xy"
If x equals 0 and y equals 1 then xy equals?
If ( x = 0 ) and ( y = 1 ), then ( xy = 0 \times 1 = 0 ). Therefore, the value of ( xy ) is 0.
What does X times Y equal with no variables?
It equals XY.
If x equals -8 and xy equals 1 what does y equal?
So far you know that: x=-8 xy=1 so xy means x times y. If you split xy. y=1/x or y=1/-8 1/-8= -0.125 You can find out that this is correct with the formula xy=1 because -0.125 x -8 is 1.
What is the GCF of x squared y and xy squared?
The GCF is xy
X plus XY equals 8 solve for Y?
x+xy=8 xy=-x+8 y=-1+8/x
What is the result of xy?
The result of ( xy ) is simply the product of the two variables ( x ) and ( y ). To determine the value, you would need specific numerical values for both ( x ) and ( y ). If, for example, ( x = 3 ) and ( y = 4 ), then ( xy = 3 \times 4 = 12 ). Without specific values, ( xy ) remains as the expression itself.
What is the what is the LCM of Y Y and Y?
It is: x times y or as xy
The sum of xy times 3?
The sum of xy times 3 is equal to 3(xy).
If xy equals x or yx equals x what is y?
xy = x ÷x y = 1
If x4and y2 the value of xy squared?
To find the value of (xy^2) given (x = 4) and (y = 2), substitute the values into the expression. This gives (xy^2 = 4 \times (2^2) = 4 \times 4 = 16). Therefore, the value of (xy^2) is 16.
How do you factor xy x?
Oh, what a happy little question! To factor out xy from xy, you simply take out the common factor, which is xy itself. So, the factored form of xy is just xy. Isn't that just lovely? Just remember, there are no mistakes in math, only happy little accidents.
