y = -x/3 + c (where c is any constant)
Two lines that are perpendicular have gradients that multiply together to make -1
-3
3x+y = 4 y = -3x+4 Perpendicular slope: 1/3
15
y = 1/3x+4
No, the two lines are not perpendicular.
If a line has equation y = mx + c, the perpendicular line has gradient -1/m A line perpendicular to 3x + y = 2 has equation 3y = x + c; the value for c will be determined by a point through which the line must pass.
-4
- 1/3
Slope of given line = -3 Therefore, slope of perpendicular = 1/3
-1
4y= -3x + 12 y = -3/4x + 3 The perpendicular slope is 4/3
y - 3x = 8 standard form is y = mx + b m = slope y = 3x + 8 in this form slope m is 3 The perpendicular line slope is the negative inverse of m -1/m = -1/3