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All of the four-digit multiples of 400 end in 00.

Q: What must a four digit number end in to be divisible by 400?

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There can be no such number. If it is divisible by 5 and 6it must be divisible by 6.

To be divisible by 36 the number must be divisible by 9 (and 4). To be divisible by 9, the sum of the digits must be divisible by 9. 5 + 5 = 10 → need an extra 8 → A + B = 8.

Not necessarily. For example, the number 56 ends in a 6 but is not divisible by six. To check if a number is divisible by six, the number must be divisible by both 2 and 3. To check this, the last digit must be even and the sum of the digits must be divisible by three. If the number meets these conditions, it is in fact divisible by six.

Look at the last digit of the number; if it is even then the number is divisible by 2, otherwise it is not.

No. In order for a number to be divisible by 10, the ones digit must be zero (0).

Related questions

A number divisible by 123456789 must be 0 or bigger than 123456789. It must, therefore have 1 digit or 9 digits (or more). A remainder of 1 makes no difference to the number of digits. In any case, there can be no number of 4 digits that is divisible by 123456789.

Any number (however many digits) that is divisible by 3 and by 4 MUST be divisible by 6. So there cannot be a number that meets the requirements of the question.

yes 552 is divisible by 6 and the result is 92... to find out if a number is divisible by 6 then that number must be divisible by 2 and 3.. 1.If a number is divisble by three then the last digit must be divisible by 2 (so that the last digit must be 0,2,4,6,8) in this number the last digit is 2 so that it is divisible by 2 2.If a number is divisble by 3 then the sum of its digit must be divisible by 3. In this case the sum of the digits of 552 is 5+5+2= 12 and 12 is divisible by 3.... If this two rules fit in then that number is divisible by 6

There can be no such number. If it is divisible by 5 and 6it must be divisible by 6.

To be divisible by 36 the number must be divisible by 9 (and 4). To be divisible by 9, the sum of the digits must be divisible by 9. 5 + 5 = 10 → need an extra 8 → A + B = 8.

Not necessarily. For example, the number 56 ends in a 6 but is not divisible by six. To check if a number is divisible by six, the number must be divisible by both 2 and 3. To check this, the last digit must be even and the sum of the digits must be divisible by three. If the number meets these conditions, it is in fact divisible by six.

Look at the last digit of the number; if it is even then the number is divisible by 2, otherwise it is not.

No. If any number is divisible by 5 and 6, it must also be divisible by 30, which means that it must end with a zero.

No. In order for a number to be divisible by 10, the ones digit must be zero (0).

If the number formed by the last three digits is divisible by 8. This requires that: if the digit in the hundreds place is even, the last two digits must form a number divisible by 8 and if the digit in the hundreds place is odd, the last two digits must form a number divisible by 4 but not by 8.

An even number, by definition is divisible by 2. For the number to be divisible by 10, the last digit must be 0, which ensures it is an even number. Any number, with zero as the last digit will satisfy the requirements. So 111110 will do.

To be divisible by 2 the number must be even, that is its last digit must be 2, 4, 6, 8, or 0; the last digit of 432 is 2 which is one of {2, 4, 6, 8, 0} so 432 is even and divisible by 2. To be divisible by 3 sum the digits of the number; if this sum is divisible by 3 then the original number is divisible by 3. The test can be repeated on the sum until a single digit remains, in which case if this single digit is 3, 6, or 9 then the original number is divisible by 3; For 432: 4 + 3 + 2 = 9 which is one of {3, 6, 9} so 432 is divisible by 3. To be divisible by 5 the last digit must be a 0 or 5; the last digit of 432 is a 2 which is not 0 nor 5, so 432 is not divisible by 5. To be divisible by 6, the number must be divisible by both 2 and 3; these have been tested above and found to be true, so 432 is divisible by 6. To be divisible by 9 sum the digits of the number; if this sum is divisible by 9 then the original number is divisible by 9. The test can be repeated on the sum until a single digit remains, in which case if this single digit is 9 then the original number is divisible by 9; For 432: 4 + 3 + 2 = 9 which is 9 so 432 is divisible by 9 To be divisible by 10 the last digit must be a 0; the last digit of 432 is a 2 which is not 0, so 432 is not divisible by 10. 432 is divisible by 2, 3, 6 and 9, but not divisible by 5 nor 10.