13
5/8
403÷8 gives 50 as quotient and 3 as remainder. Dividend- remainder=divisor ×quotient 403-3=8*50 which is 400. our value is 403 So increase divisor 8*51=408. 403+5 gives 408. So 5 must be added to 403 to get a no divisible by 8.
To determine the smallest number that must be added to 403 to make it divisible by 8, first find the remainder when 403 is divided by 8. The remainder is 3 (since 403 ÷ 8 = 50 with a remainder of 3). To make it divisible by 8, you need to add 5 (8 - 3 = 5). Therefore, the smallest number to add is 5.
2
Positive 29.... -21 + 29 = 8
5/8
5
It is: (-5*9)+67 = 22
22
5/8
To find the number that must be added to -19 to get -11, you can set up the equation: -19 + x = -11. Solving for x, you add 19 to both sides, resulting in x = -11 + 19, which simplifies to x = 8. Therefore, the number that must be added to -19 is 8.
36010