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What number is divisible by 2 3 4 5 6 and gives you a remainder of 1?
Wiki User
∙ 13y ago
6! which equals 6x4x3x2x1=24x6=144
Wiki User
∙ 13y ago
LUVV WILSON
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Is 121 divisible by 3?
No. Add the digits of the dividend and if that is divisible by 3 then the original number is divisible by 3; if not, its remainder when divided by 3 gives the remainder when the original number is divided by 3: 1 + 2 + 1 = 4 which gives a remainder of 1 when divided by 3, so 121 divided by 3 gives a remainder of 1. (121 = 40 x 3 + 1)
What four digit number is divisible by 123456789 with a remainder of one?
A number divisible by 123456789 must be 0 or bigger than 123456789. It must, therefore have 1 digit or 9 digits (or more). A remainder of 1 makes no difference to the number of digits. In any case, there can be no number of 4 digits that is divisible by 123456789.
Is 104 divisible by 9?
No. To check if a number is divisible by 9 add the digits together and if the sum is divisible by 9 then so is the original number. The check can be used on the sum so keep summing until a single digit remains. If this digit is 9, then the number is divisible by 9, otherwise it gives the remainder when the number is divided by 9. (This single digit is known as the digital root of the number.) 104 → 1 + 0 + 4 = 5 5 is not 9, so 104 is not divisible by 9; it has a remainder of 5 when divided by 9
What is special about the number 2520?
it's the smallest number divisible without remainder by the numbers 1 to 10.
Is 60 divisible by 8?
2 x 6 + 0 = 12 2 x 1 + 2 = 4 4 is not [divisible by] 8, so 60 is not divisible by 8. (The remainder when 60 is divided by 8 is 4). To test divisibility by 8: Add together the hundreds digit multiplied by 4, the tens digit multiplied by 2 and the units (ones) digit. If this sum is divisible by 8 so is the original number. (Otherwise the remainder of this sum divided by 8 is the remainder when the original number is divided by 8.) If you repeat this sum on the sum until a single digit remains, then if that digit is 8, the original number is divisible by 8 otherwise it gives the remainder when the original number is divided by 8 (except if the single digit is 9, in which case the remainder is 9 - 8 = 1).
Is 121 divisible by 3?
No. Add the digits of the dividend and if that is divisible by 3 then the original number is divisible by 3; if not, its remainder when divided by 3 gives the remainder when the original number is divided by 3: 1 + 2 + 1 = 4 which gives a remainder of 1 when divided by 3, so 121 divided by 3 gives a remainder of 1. (121 = 40 x 3 + 1)
Which number is completely divisible by 7 and by 23456 and gives remainder as 1?
The number would be (7x23456) + 1 = 164193
Is 13 divisible by 3?
No 13 is not divisible by 3 because there would be a remainder of 1 and a number that is divisible by another should have no remainder
What whole number when divided by 2 has the remainder of 1 and divided by 4 has the remainder of 2?
It is not possible, because the number 4 is divisible by 2, and it's remainder is divisible by 2 also, so whatever number works for the "4 with a remainder of 2", will never work for "2 with a remainder of 1.
Is the number 33121 evenly divisible by the number 3?
No because it will have a remainder of 1
Is 85 divisible by 4?
85 is not exactly divisible by 4. Dividing 85 by 4 gives 21 with a remainder of 1.
What is the biggest remainder you can get if you divide by 2?
1, any number that you divide by 2 is either divisible by 2 (even) or not divisible by 2, leaving a remainder of 1 (odd).
Is 15345 divisible by 1?
When you divide a number by 1, it remains the same. A number is considered divisible is the resulting answer is an integer with no remainder left over. Thus, if the starting number is an integer, it will be divisible by 1. 15345 is an integer, and thus is divisible by 1.
What is the smallest digit that can be placed in the blank so that 8-6935 can be divisible by 3?
2. To test a number to be divisible by 3, add up the digits and if the sum is divisible by 3, so is the original number. If not, the excess over a multiple of 3 gives the remainder when the original number is divided by 3. Subtract this remainder from 3 and this gives the smallest digit to replace the blank; unless the remainder is 0, in which case the blank can be replaced by a 0: 8 + 6 + 9 + 3 + 5 = 31 → 31 ÷ 3 = 10 remainder 1 Replace blank by 3 - 1 = 2: 826935 is divisible by 3
Is 234 divisible by 9?
Yes, 234 is divisible by 9 because on dividing 234 by 9 we get 26 as quotient and 0 as remainder. A number is divisible by another number if: 1- Quotient is a whole number 2- Remainder is zero
Why do prime numbers have a remainder of 1 or 5 when divided by 6?
If the number has a remainder of 2 or 4 when divided by 6, it is an even number, so it is not prime number. 6n + 2 = 2 (3n + 1), so it is divisible by 2. 6n + 4 = 2 (3n + 2), so it is divisible by 2. If the number has a remainder of 3 when divided by 6, it is divisible by 3, so it is not a prime number. 6n + 3 = 3 (2n + 1), so it is divisible by 3. However, there are two prime numbers that do not have a remainder of 1 or 5 when divided by 6 : 2 and 3
What four digit number is divisible by 123456789 with a remainder of one?
A number divisible by 123456789 must be 0 or bigger than 123456789. It must, therefore have 1 digit or 9 digits (or more). A remainder of 1 makes no difference to the number of digits. In any case, there can be no number of 4 digits that is divisible by 123456789.
