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Q: What number is twice the product of its two digits?

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362x(3x6)

The digits product of two digit has number four

When using significant digits, the product has only the number of significant digits as the lowest number in the factors. "20" has two significant digits and "310" has three. Therefore, the product has to have two significant digits. 310 Ã— 20 = 6200 6200 already has two significant digits.

18 is the only number that matches these criteria.

There are two numbers that satisfy the criteria. 38 and 83

It is 11.

24

12 or 24

The 2-digit number must be 20, because it is the only 2-digit number whose sum of its two even digits, 2 + 0 = 2, is greater than the product of its two even digits, 2 x 0 = 0. Moreover, 20 is a product of the two consecutive integers 4 and 5.

-- "The sum of a two-digit number" is unclear. I took it to mean"The sum of the digits of a two-digit number."-- "... the product ?" is unclear. Are you looking for the product of the two digits,or the product of the forward and backward numbers ?-- It's not possible to write a number whose two digits sum to 12 and whosereverse exceeds it by 25. The tens digit would have to be 4.611... and the unitsdigit would have to be 7.388... .Then(4.611...) + (7.388...) = 12(46.111...) + (7.388...) = 53.5(73.888...) + (4.611...) = 78.5Difference = 25So, the number can't be written, but ...The product of its two digits is 34.071 (rounded)The product of the forward and reverse numbers is 4,199.75 (rounded)

two

Take the smallest 2-digit number (10), and see how many digits you get when you multiply it by itself.Also, take the largest possible 2-digit number (99), and see how many digits you get when you multiply it by itself.

21 or 35

55.

12

98

25 can be either the product of 1 and 25, or the product of 5 and 5. Since there are two digits in the number, the answer can only be 55. This makes sense, since 55 is divisible by 5, and the product of 5 and 5 is 25.

22

The number is 35.

It can only be a multipule of 6. 12.

The Answer is 36 btw. 3 + 6 = 9 3 x 6 = 2(3x6) 2(18) = 36

If you mean, "What is the largest number of digits possible in the product of two 2-digit numbers" then 99 * 99 = 9801, or 4 digits. Anything down to 59 * 17 = 1003 will have 4 digits.

121 because 2x1x1=2 and 11x11=121

In the everyday decimal system of writing numbers . . .-- The largest two digits are 8 and 9.-- Their product is 72.-- 10 less than that is 62 .

two digits