47 Impossible problem!
Well, isn't that a happy little puzzle! Let's think about this together. Since the number is greater than 50 and has two digits, the only number that fits is 93. The digits are 9 and 3, with 3 being half of 9, and it's a lovely odd number!
1346
18. 1+8=9 9x2=18
If the lead digit cannot be zero then there are 9 x 9 x 8 x 7 = 4536 combinations. If the lead digit can be zero then there are, 10 x 9 x 8 x 7 = 5040 combination.
804
The units digit of a two digit number exceeds twice the tens digit by 1. Find the number if the sum of its digits is 10.
It is 99,887,765
18 is the only number that matches these criteria.
The Answer is 36 btw. 3 + 6 = 9 3 x 6 = 2(3x6) 2(18) = 36
17
2.3
22621, 44742, 66863, 88984
36 is twice the product of its digits multiplied. 3 times 6 equals 18, and 18 times 2 equals 36.
47 Impossible problem!
The number is 84.Assign the digits in the number the letters a and b.GIVEN: a + b = 12GIVEN: a = 2bSolve for b, then solve for a.2b + b = 123b = 12b = 4a = 2(4) = 8
9218 9425