18 is the only number that matches these criteria.
The units digit of a two digit number exceeds twice the tens digit by 1. Find the number if the sum of its digits is 10.
2.3
9218 9425
I am a 3 digit number divisible by 7 but not 2 the sum of my digits is 4 what number am I
The number is 84.Assign the digits in the number the letters a and b.GIVEN: a + b = 12GIVEN: a = 2bSolve for b, then solve for a.2b + b = 123b = 12b = 4a = 2(4) = 8
The units digit of a two digit number exceeds twice the tens digit by 1. Find the number if the sum of its digits is 10.
None. The sum of one digit can't be twice the size of the digit.
2.3
47 Impossible problem!
9218 9425
I am a 3 digit number divisible by 7 but not 2 the sum of my digits is 4 what number am I
The number is 84.Assign the digits in the number the letters a and b.GIVEN: a + b = 12GIVEN: a = 2bSolve for b, then solve for a.2b + b = 123b = 12b = 4a = 2(4) = 8
A) If a number has two digits, then the sum of its digits is less than the value of the original two-digit number.
Only one . . . . . 18
81
49
Well 18 works. [1+8 = 9]. It's not exactly the only one, though. Consider zero. The sum of the digits (0) is zero. And twice zero = zero.Here are some ideas to see if there are others: For 1-digit numbers, the number is the sum, so the zero, above, is the only one that satisfies the conditions. For 2-digit numbers, the largest sum possible is 18 [99: 9 + 9]. Twice that sum is 36, so no numbers greater than 36 (with 2-digit numbers).Now consider the unknown number with digits AB. So the sum = A + B, and the number = 10*A + B. Now the number is twice the sum, so:10*A + B = 2*(A + B). Rearranging, we have 8*A = B, so you can substitute whole numbers for A, and calculate B. There is the trivial case of zero: 8*0 = 0, which was already covered. If A = 1, then B = 8, which gives us 18. With A = 2, then B= 16, so that's not a 2-digit number. So 18 is the only 2-digit number.What about 3-digits: the largest 3-digit sum is 9+9+9=27. Twice that is 54, which is a 2-digit number. So there can be no 3-digit numbers, satisfying the conditions.