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What two digit number is twice the sum of its digits?
18 is the only number that matches these criteria.
I am a two-digit number divisible by 5 and the product of my digits is 25 what is the answer?
25 can be either the product of 1 and 25, or the product of 5 and 5. Since there are two digits in the number, the answer can only be 55. This makes sense, since 55 is divisible by 5, and the product of 5 and 5 is 25.
The sum of the digits of a two digit number is 9 the number itself is equal to twice the product of its digit find the number?
The Answer is 36 btw. 3 + 6 = 9 3 x 6 = 2(3x6) 2(18) = 36
How many digits can the product of 2-digit numbers have?
If you mean, "What is the largest number of digits possible in the product of two 2-digit numbers" then 99 * 99 = 9801, or 4 digits. Anything down to 59 * 17 = 1003 will have 4 digits.
If the sum of two digits is 8 and the product is 12 and the number is between 30 and 90?
2 and 6
What two digit number is twice the product of its digits?
362x(3x6)
What is 310 times 20 in significant digits?
When using significant digits, the product has only the number of significant digits as the lowest number in the factors. "20" has two significant digits and "310" has three. Therefore, the product has to have two significant digits. 310 × 20 = 6200 6200 already has two significant digits.
What two digit number is twice the sum of its digits?
18 is the only number that matches these criteria.
What number has 24 as the product of its digits and the sum of its digits is a prime number?
There are two numbers that satisfy the criteria. 38 and 83
What The two digits of a number are the same. their product is not composite. what is the number?
It is 11.
If the sum of a two digit number is 12 and the digits interchange their places the new number exceeds the original number by 25 what is the product?
-- "The sum of a two-digit number" is unclear. I took it to mean"The sum of the digits of a two-digit number."-- "... the product ?" is unclear. Are you looking for the product of the two digits,or the product of the forward and backward numbers ?-- It's not possible to write a number whose two digits sum to 12 and whosereverse exceeds it by 25. The tens digit would have to be 4.611... and the unitsdigit would have to be 7.388... .Then(4.611...) + (7.388...) = 12(46.111...) + (7.388...) = 53.5(73.888...) + (4.611...) = 78.5Difference = 25So, the number can't be written, but ...The product of its two digits is 34.071 (rounded)The product of the forward and reverse numbers is 4,199.75 (rounded)
A 2 digit number that is the product of 2 consecutive integers and the sum of its digits is greater than the product of the digits both digits are even?
The 2-digit number must be 20, because it is the only 2-digit number whose sum of its two even digits, 2 + 0 = 2, is greater than the product of its two even digits, 2 x 0 = 0. Moreover, 20 is a product of the two consecutive integers 4 and 5.
The two digit number that is divisible by the sum and the product of its digits?
12 or 24
Its is the greatest even two-digit number The product of its digits is 72?
24
I am a two-digit number divisible by 5 and the product of my digits is 25 what is the answer?
25 can be either the product of 1 and 25, or the product of 5 and 5. Since there are two digits in the number, the answer can only be 55. This makes sense, since 55 is divisible by 5, and the product of 5 and 5 is 25.
The sum of the digits of a two digit number is 9 the number itself is equal to twice the product of its digit find the number?
The Answer is 36 btw. 3 + 6 = 9 3 x 6 = 2(3x6) 2(18) = 36
What number am I I am a multiple of 7 and a factor of 210. The product of my two digits is odd. What number am I?
21 or 35
